calling python module dynamically using exec

Question

I have 2 modules

mexec1.py

def exec1func():
    print 'exec1'
    exec 'c:/python27/exec2.py'

if __name__ == '__main__':
    exec1func()

exec2.py

def exec2func(parm=''):
    print 'exec2 parm',parm

if __name__ == '__main__':
    exec2func(parm='')

From exec1.py I want to call exec2func of the exec2.py using only exec or execfile...I don't want subprocess.Popen..

nneonneo · Accepted Answer · 2012-10-25 03:33:59Z

2

Use import instead:

def exec1func():
    from exec2 import exec2func
    exec2func()

If you want to import using the full path, use imp.load_source:

import imp

def exec1func():
    exec2 = imp.load_source('exec2', 'c:/python27/exec2.py')
    exec2.exec2func()

answered Oct 25, 2012 at 3:33

nneonneo

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Comments

Keith · Accepted Answer · 2012-10-25 04:37:00Z

0

It would be better to make it a module and import it. If you need dynamic imports use importlib.

mod = importlib.import_module("exec2", package=None)
mod.exec2func()

answered Oct 25, 2012 at 4:37

Keith

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@nneonneo That method does not deal with packages. But for a base module it would work.