Convert Json Array to Java Array

Question

I'm trying to convert this JSON string into an array:

{"result":"success","source":"chat","tag":null,"success":{"message":"%message%","time":%time%,"player":"%player%"}}

I would like to output it like this:

<%player%> %message%

I'm very new to java, I came from PHP where you could just do somthing along the lines of:

$result = json_decode($jsonfile, true);
echo "<".$result['success']['player']."> ".$result['success']['message'];

Output: <%player%> %message%

Is there an easy way to do this in java?

I searched for some similar topics but I didn't really understand them. Could someone explain this to me like I'm 5?

Where is your Java code?

user647772
– user647772

2012-11-08 09:32:17 +00:00
Commented Nov 8, 2012 at 9:32 — user647772
– user647772, Commented Nov 8, 2012 at 9:32

Abubakkar · Accepted Answer · 2012-11-08 09:32:26Z

2

Why reinvent the wheel, use GSON - A Java library that can be used to convert Java Objects into their JSON representation and vice-versa

answered Nov 8, 2012 at 9:32

Abubakkar

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Yasin Okumuş · Accepted Answer · 2012-11-08 09:42:52Z

1

JSON-lib is a good library for JSON in Java.

String jsonString = "{message:'%message%',player:'%player%'}";
JSONObject obj = JSONObject.fromObject(jsonString);    
System.out.println("<" + obj.get("message") + ">" + obj.get("player") );

answered Nov 8, 2012 at 9:42

Yasin Okumuş

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2 Comments

Jeremy Over a year ago

I've got: import net.sf.json.*;at the top with the other imports then your code, I get the errors

Exception in thread "main" java.lang.NoClassDefFoundError: org/apache/commons/lang/exception/NestableRuntimeException Caused by: java.lang.ClassNotFoundException: org.apache.commons.lang.exception.NestableRuntimeException

when trying to run it, What did I do wrong?

Yasin Okumuş Over a year ago

You must import the dependencies of the JSON-lib as well. It depends on Apache Commons too, so you got that error: > Json-lib requires (at least) the following dependencies in your classpath: > jakarta commons-lang 2.5 > jakarta commons-beanutils 1.8.0 > jakarta commons-collections 3.2.1 > jakarta commons-logging 1.1.1 > ezmorph 1.0.6

Sumit Desai · Accepted Answer · 2012-11-08 09:36:31Z

0

You can also use xStream for doing it which has got a very simple API. Just Google for it.

answered Nov 8, 2012 at 9:36

Sumit Desai

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Kumar Vivek Mitra · Accepted Answer · 2012-11-08 09:42:37Z

You can always use the following libraries like:

- Jackson

- GSON

Ok here is the right way to do it Without using any library:

Eg:

JSONArray jarr = api.giveJsonArr();

// giveJsonArr() method is a custom method to give Json Array.

for (int i = 0; i < jarr.length(); i++) {

   JSONObject jobj = jarr.getJSONObject(i);   // Taking each Json Object

   String mainText = new String();            // fields to hold extracted data
   String provText = new String();
   String couText = new String();
   String fDatu = new String();

   try {
     mainText = jobj.getString("Overview");   // Getting the value of fields
     System.out.println(mainText);
    } catch (Exception ex) {

    }

    try {

    JSONObject jProv = jobj.getJSONObject("Provider");
    provText = jProv.getString("Name");
    System.out.println(provText);
    } catch (Exception ex) {

    }

    try {
        JSONObject jCou = jobj.getJSONObject("Counterparty");
        couText = jCou.getString("Value");
        System.out.println(couText);
    } catch (Exception ex) {

    }

    try {
                String cloText = jobj.getString("ClosingDate");
        fDatu = giveMeDate(cloText);
        System.out.println(fDatu);
        } catch (Exception ex) {

        }

   }

Tobias Ritzau · Accepted Answer · 2012-11-08 09:46:14Z

0

As you see you have many alternatives. Here is a simple one from json.org where you find lots of other alternatives. The one they supply them selves is simple. Here is your example:

    String json = "{\"result\":\"success\",\"source\":\"chat\",\"tag\":null,\"success\":{\"message\":\"%message%\",\"time\":%time%,\"player\":\"%player%\"}}";
    JSONObject obj = new JSONObject(json);
    JSONObject success = obj.getJSONObject("success");
    System.out.println("<" + success.get("player") + "> "
                       + success.get("message"));

answered Nov 8, 2012 at 9:46

Tobias Ritzau

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