Possible Duplicate:
How to initialize a list to a certain value in Python
In Java, I can do this:
int[] i = new int[5];
and all elements of i will be 0.
How can I do the same for python, I am doing like this:
i = [0, 0, 0 , 0, 0]
is there a cleaner/simpler way?
You can use the * operator:
i = [0] * 5
Demo:
>>> i = [0] * 5
>>> i
[0, 0, 0, 0, 0]
Oh, and i is a bad naming choice. People expect i to be a numeric loop variable.
i = [0] * 5
Warning: be careful when the things in the list are mutable objects, such as nested lists. You're making five references to the same object, which will bite you when you start manipulating the list items. With integers and strings, it's fine, though. For mutable objects:
i = [[] for _ in xrange(5)] # range(5) on Python 3.x
Using a list comprehension:
i = [0 for j in range(5)]
You can also use this to build more complex arrays:
A = [[0 for i in range(5)] for j in range(5)]
i = [[0]] * 5
append()method.