Delete a dynamic array but keep a pointer

Question

I have made a function for expanding array, and this function is inside a class.

Because this function creates new_arr and copies all the numbers of array into the new_arr and at the end sets pointer of array with new_arr, I wold like to know how to delete numbers in array becuse I dont need it any more

void Array::bigger() {
    int  new_size = size * 2;
    int *new_arr = new int[new_size];
    for (int f1=0; f1<last; f1++) {
        new_arr[f1] = array[f1];
    }
    this->size = new_size;
    array = new_arr;
}

Thanks

delete[] array; before array = new_arr;. You could also use std::copy() to copy array to new_arr. You could also use std::vector<int> and forget about dynamic memory management. — hmjd
– hmjd, Commented Nov 16, 2012 at 11:23

juanchopanza · Accepted Answer · 2012-11-16 11:29:39Z

4

Assuming this is an exercise, then delete the array before re-assigning to the new one:

delete [] array;
array = new_arr;

In real code, use an std::vector<int> instead of the dynamically allocated array.

edited Nov 16, 2012 at 11:29

answered Nov 16, 2012 at 11:22

juanchopanza

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Comments

Denis Ermolin · Accepted Answer · 2012-11-16 11:22:30Z

3

free memory before lose pointer to it:

void Array::bigger() {
    int  new_size = size * 2;
    int *new_arr = new int[new_size];
    for (int f1=0; f1<last; f1++) {
        new_arr[f1] = array[f1];
    }
    this->size = new_size;
    delete[] array; //free memory
    array = new_arr;
}

answered Nov 16, 2012 at 11:22

Denis Ermolin

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1 Comment

depecheSoul Over a year ago

Thanks, your answer is so simple

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