PHP mysql select concat

Question

i have this function that shows an autosuggest in a form:

function searchbyId($params) {

    $input = strtolower($params['input']);
    $len = strlen($input);
    $limit = isset($params['limit']) ? (int) $params['limit']:25;
    $items=array();
    $sql='SELECT DISTINCT nIdentidad, CONCAT(primerNombre, ' ', segundoNombre, ' ', primerApellido, ' ', segundoApellido) AS nombre FROM tarjeta_indent WHERE nIdentidad LIKE \''.$input.'%\' ORDER BY nIdentidad LIMIT '.$limit;
    $resp=db_query($sql);
    if($resp && db_num_rows($resp)){
        while(list($nIdentidad)=db_fetch_row($resp)) {
            //$name=(strpos($name,'@')===false)?$name:'';
            $items[] ='{"id": "'.$nIdentidad.'", "value": "'.$nIdentidad.'"}';

        }
    }
    $result= '{"results": ['.implode(", ", $items).']}';
    return $result;
}

but only works if i change the query to this:

$sql='SELECT DISTINCT nIdentidad FROM tarjeta_indent WHERE nIdentidad LIKE \''.$input.'%\' ORDER BY nIdentidad LIMIT '.$limit;

How can i do the concat part?

Thanks.

and this doesn't work ... how? remember that select distinct applies to the ENTIRE row. it's not "distinct nIdentidad values". — Marc B
– Marc B, Commented Nov 16, 2012 at 14:48

meustrus · Accepted Answer · 2012-11-16 15:16:47Z

I feel like this is decidedly simple, but you have a syntax error in your concat statement; you're using single quotes to escape strings but the PHP string is defined with single quotes:

$sql='SELECT DISTINCT nIdentidad, CONCAT(primerNombre, ' ', segundoNombre, ' ', primerApellido, ' ', segundoApellido) AS nombre FROM tarjeta_indent WHERE nIdentidad LIKE \''.$input.'%\' ORDER BY nIdentidad LIMIT '.$limit;

How about this?

$sql = sprintf(<<<SQL
    SELECT
      DISTINCT nIdentidad,
      CONCAT(primerNombre, ' ', segundoNombre, ' ', primerApellido, ' ', segundoApellido) AS nombre
    FROM tarjeta_indent
    WHERE nIdentidad LIKE '%s'
    ORDER BY nIdentidaa
    LIMIT %d
SQL
  , mysql_real_escape_string($input), $limit);

If I'm right about db_query and you're using Drupal, try this instead (for Drupal 7):

$sql = <<<SQL
    SELECT
      DISTINCT nIdentidad,
      CONCAT(primerNombre, ' ', segundoNombre, ' ', primerApellido, ' ', segundoApellido) AS nombre
    FROM tarjeta_indent
    WHERE nIdentidad LIKE :input
    ORDER BY nIdentidaa
    LIMIT :limit
SQL;
$resp = db_query($sql, array(':input' => $input, ':limit' => $limit));

This would be the Drupal 6 version:

$sql = <<<SQL
    SELECT
      DISTINCT nIdentidad,
      CONCAT(primerNombre, ' ', segundoNombre, ' ', primerApellido, ' ', segundoApellido) AS nombre
    FROM tarjeta_indent
    WHERE nIdentidad LIKE %s
    ORDER BY nIdentidaa
    LIMIT %d
SQL;
$resp = db_query($sql, $input, $limit);

Ed Manet · Accepted Answer · 2012-11-16 14:53:29Z

0

CONCAT will work with strings/varchar, but not with numbers. So if primerNombre and segundNombre are INT data types, CONCAT will fail. Try using the CONVERT function:

SELECT DISTINCT nIdentidad, 
       CONCAT( CONVERT(primerNombre, char(8)), ' ', 
               CONVERT(segundoNombre, char(8))  ) as nombre

answered Nov 16, 2012 at 14:53

Ed Manet

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2 Comments

user995691 Over a year ago

primerNombre and segundNombre are text. When i run my query in mysql works fine.

fancyPants Over a year ago

Try select concat('whatever', 1, 'voodoo') -> no convert needed.

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