Function name in Array

Question

I have a problem in calling a function that the name is being stored in an array.

class tempClass {
   function someFunction() {
      $tempArray = array('functionName' => 'tempFunction');
      $tempArray['functionName']();
   }

   function tempFunction() {
      echo "inside function";
   }
}

It gives me an error:

"Fatal error: Call to undefined function tempFunction() in /..... line..".

Line number is the line where the function is being called, $tempArray['functionName']();

But if called the method_exists(), it shows that the method is exists. It is very confusing. Can anyone please help me out? Thanks.

possible duplicate of Can you store a function in a PHP array? — Donal Fellows
– Donal Fellows, Commented Nov 25, 2012 at 15:34

Nelson Benítez León · Accepted Answer · 2012-11-25 13:39:17Z

4

Use call_user_func() , like this:

call_user_func($tempArray['functionName']);

UPDATE:
As you want to call a method of a class from inside that class, use the following instead:

call_user_func(array($this, $tempArray['functionName']));

See working demo

edited Nov 25, 2012 at 13:39

answered Nov 25, 2012 at 13:25

Nelson Benítez León

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7 Comments

Abhishek Salian Over a year ago

I got this error "Warning: call_user_func() expects parameter 1 to be a valid callback, function 'tempFunction' not found or invalid function name in...."

arkascha Over a year ago

Same problem as with your original attempt: you are missing the scope.

Abhishek Salian Over a year ago

yes you are right, How stupid of me. I used $this->$tempArray['functionName'](); and it worked. Thanks a lot guys.

Nelson Benítez León Over a year ago

@AbhishekSalian I've updated my answer with a corrected version for your case (calling a method of the class from within the class), check it out.

Nelson Benítez León Over a year ago

@arkascha Yes I didn't notice it first time, check out my update for the fixed version.

|

arkascha · Accepted Answer · 2012-11-25 13:56:56Z

2

Well you ask if the method exists inside the class or object, but you call it without that scope. That won't work...

Try this instead:

call_user_method($tempArray['functionName'],$this);

Just saw that call_user_method() is depreciated. Use call_user_func() as answered by Nelson instead.

edited Nov 25, 2012 at 13:56

answered Nov 25, 2012 at 13:27

arkascha

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3 Comments

Abhishek Salian Over a year ago

it didnt work with the above cmd but i just added the scope to the calling function. thanks.

Nelson Benítez León Over a year ago

This answer does not work, the error can be seen here codepad.org/CIT7IDhT

arkascha Over a year ago

@Nelson: that is true, sorry for that. I corrected the answer, but Nelsons answer is better: just saw that call_user_mothod is depreciated! Sorry for the confusion.

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