I have module foo, inside this module I dynamically created class:
def superClassCreator():
return type("Bar", (object,), {})
Now, what I want to achieve is to make this new dynamic class visible as a class of this module:
import foo
dir(foo)
>>> [... 'Bar' ...]
Do you know how to do this?
You can use Bar = superClassCreator() in foo (at the module level).
Alternatively, from another module, you can add Bar as an attribute on foo:
import foo
foo.Bar = superClassCreator()
or, if the name must be taken from the generated class:
import foo
generatedClass = superClassCreator()
setattr(foo, generatedClass.__name__, generatedClass)
From within the foo module, you can set it directly on globals():
generatedClass = superClassCreator()
globals()[generatedClass.__name__] = generatedClass
del generatedClass
with an optional del statement to remove the generatedClass name from the namespace again.
sys.modules. Use setattr(sys.modules[generatedClass.__module__], generatedClass.__name__, generatedClass). Note that __module__ is going to be the module in which superClassCreator() is defined.__module__ attribute, btw. You can also provide a __module__ key in the dict argument to type(). So type('Bar', (object,), {'__module__': 'foo.baz'}). I've verified the C source of type(), it takes __name__ from the current globals. So it's your Django shell mucking about.