Possible Duplicate:
How can I convert integer into float in Java?
I got the problem with this code.
I have two variable int i and float f.
int i = 23;
float f = i/10;
I suppose the value in f variable should be 2.3
but the real output value in f is 2.0
Why result occurred like this and how can i get the float value 2.3
float f = i/10
is using integer arithmetic (both numerator and denominator are integers). The result is then promoted to a float type.
If you do
float f = i/10f
then you'll force floating point arithmetic (the denominator is now non-integer). The successive f indicates that 10f is treated as floating point. Specifying 10.0 or 10d would indicate a double.
double (and compiler error), not float. Should be i/10f
The output is 2.0f because both the numerator and denominator are integers hence it is using integer arithmetic.
i/10 returns 2 which when typecasted to float, converted to 2.0f.
You need to typecast atleast one of the num/denominators to float to make FP division
int i = 23;
float f = (float)i/10;
or
float f = i/10f;
Possible ways for this.
float z = (float) x / y;
or
float z = x / (float) y;
or(not required)
float z = (float) x / (float) y;
please try
instead of your
i/10 use
i/1Of
int i = 1;
float f = (float) i;
You can consider it as a 2 step operation
int i = 23;
int tmp = i/10;
// tmp = 2
float f = (float) tmp;
// f = 2.0f
And this is how it looks like in bytecode
L0 //int i = 23;
BIPUSH 23
ISTORE 1 // var 1 is 'i'
L1 // int tmp = i/10;
ILOAD 1
BIPUSH 10
IDIV // integer division
ISTORE 2 // var 2 - is tmp
L2 // float f = (float) tmp;
ILOAD 2
I2F // (float) tmp
FSTORE 3 // var 3 is 'f'
float f = (float)i/10;