Convert integer array to string at javascript

Question

Here is php code:

$arr=array(228,184,173,230,150,135,99,104,105,110,101,115,101);
$str='';
foreach ($arr as $i){
    $str.=chr($i);
}
print $str;

the output is: 中文chinese

Here is javascript code:

var arr=[228,184,173,230,150,135,99,104,105,110,101,115,101];
var str='';
for (i in arr){
    str+=String.fromCharCode(arr[i]);
}
console.log(str);

the output is: ä¸æchinese

So how should I process the array at javascript?

When I run the PHP code, I get the output ä¸æ–‡chinese. Is there anything special about your PHP configuration? — Stegrex
– Stegrex, Commented Dec 25, 2012 at 6:10
@Stegrex Maybe it is the problem of locale setting. you could try to cancel the comment zh_CN.XXX at /etc/locale.gen — solomon_wzs
– solomon_wzs, Commented Dec 25, 2012 at 6:23
I am not sure how it works out in your PHP code. But for javascript the correct array is [20013,25991,99,104,105,110,101,115,101] — Ravi Y
– Ravi Y, Commented Dec 25, 2012 at 6:25
@Stegrex: you are viewing it in ASCII. Interpret it as UTF-8. — user1233508
– user1233508, Commented Dec 25, 2012 at 6:27

PleaseStand · Accepted Answer · 2012-12-25 06:24:44Z

19

JavaScript strings consist of UTF-16 code units, yet the numbers in your array are the bytes of a UTF-8 string. Here is one way to convert the string, which uses the decodeURIComponent() function:

var i, str = '';

for (i = 0; i < arr.length; i++) {
    str += '%' + ('0' + arr[i].toString(16)).slice(-2);
}
str = decodeURIComponent(str);

Performing the UTF-8 to UTF-16 conversion in the conventional way is likely to be more efficient but would require more code.

answered Dec 25, 2012 at 6:24

PleaseStand

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2 Comments

Pacerier Over a year ago

@PleaseStand, What do you mean by "conversion in the conventional way"? What "conventional way" are you referring to?

Romain Over a year ago

Using your method I got a URIError: URI malformed

Opal · Accepted Answer · 2015-01-04 10:18:02Z

6

var arry = [3,5,7,9];
console.log(arry.map(String))

the result will be ['3','5','7','9']

var arry = ['3','5','7','9']
console.log(arry.map(Number))

the result will be [3,5,7,9]

edited Jan 4, 2015 at 10:18

Opal

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answered Jan 4, 2015 at 10:11

ingrid

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Comments

smrtl · Accepted Answer · 2013-05-17 12:07:17Z

3

Another solution without decodeURIComponent for characters up to 3 bytes (U+FFFF). The function presumes the string is valid UTF-8, not much error checking...

function atos(arr) {
    for (var i=0, l=arr.length, s='', c; c = arr[i++];)
        s += String.fromCharCode(
            c > 0xdf && c < 0xf0 && i < l-1
                ? (c & 0xf) << 12 | (arr[i++] & 0x3f) << 6 | arr[i++] & 0x3f
            : c > 0x7f && i < l
                ? (c & 0x1f) << 6 | arr[i++] & 0x3f
            : c
        );

    return s
}

answered May 17, 2013 at 12:07

smrtl

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1 Comment

Rob H Over a year ago

I tested this with Chinese, Russian, Hebrew and English, and it works. The code is not very readable, but it's the right approach.

Community · Accepted Answer · 2020-08-12 08:58:03Z

3

Seems the best way these days is the following:

function bufferToString(arr){
    return arr.map(function(i){return String.fromCharCode(i)}).join("")
}

edited Aug 12, 2020 at 8:58

CommunityBot

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answered Jul 26, 2017 at 22:22

Sancarn

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Comments

Community · Accepted Answer · 2017-04-13 12:40:36Z

1

Chinese charset has a different encoding in which one char is more than one byte long. When you do this

for (i in arr){
    str+=String.fromCharCode(arr[i]);
}

You are converting each byte to a char(actually string) and adding it to a string str. What you need to do is, pack the bytes together.

I changed your array to this and it worked for me:

var arr=[20013,25991,99,104,105,110,101,115,101];

I got these codes from here.

you can also take a look at this for packing bytes to a string.

edited Apr 13, 2017 at 12:40

CommunityBot

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answered Dec 25, 2012 at 6:33

Amit Khanna

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