Boost python argument error

Question

I just define a function as below and export it to python by using boost.python.

I have a doubt what is the corresponding type of [File* local_conf] in python.

size_t curl_conf(const char* conf_url,FILE *local_conf)
 {
     return 0;
 }


  BOOST_PYTHON_MODULE(curl_conf)
 {
     using namespace boost::python;
       def("curl_conf",curl_conf,"get conf");
 }

Tristram Gräbener · Accepted Answer · 2012-12-26 11:04:12Z

1

As quick google search and I found this blog article that seems to exactly answer your question : http://bfroehle.com/2011/10/file-and-boost-python/

You have to write a small wrapper as there is no direct conversion.

An example of the wrapper can be found here : https://gist.github.com/1265889

However, an alternative is to pass a string and open the file on the c++-side. It's up to you.

answered Dec 26, 2012 at 11:04

Tristram Gräbener

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1 Comment

hxc Over a year ago

Thanks, It needs some work to transfer from fd to FILE ,vice versa . filepath --fopen()-->FILE*; filepath--open()--fd; fd--fdopen()-->FILE*; fd--readlink(/proc/%getpid()/fd/%fd"))-->filepath;

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