Need to click on an xpath using selenium webdriver with python

Question

I have created a list of elements matching an xpath and would like to click through each successively. However, if I use the get_attribute("href") command I get a 'unicode' object has no attribute 'click' error. This is because href is a string. If I don't use get_attribute and simply use this command:

driver.find_elements_by_xpath(".//div/div/div[3]/table//tr[12]/td/table//tr/td/a")

I get a list full of elements. I can successfully click on the first link in the list; however, when I click on the second I get this error: 'Element not found in the cache - perhaps the page has changed since it was looked up' I imagine that the reason that the page links I am trying to iterate through are generated via a search query into java (this is one of the href links:

javascript:__doPostBack('ctl00$Content$listJobsByAll1$GridView2','Page$3') )

One more piece of relevant information: there are only two attributes at this xpath location: href and the text.

So, given that I am dealing with a java website and only the two attributes, I am hoping someone can tell me which webdriver commands I can use to get a series of clickable static links. Beyond a specific answer, any advice on how I could have figured this out myself would be helpful.

root · Accepted Answer · 2013-01-07 12:52:24Z

2

if you click on a link with selenium, you are changing the current page. The page that you are directed to doesn't have the next element.

to get links use:

'.//tag/@href'

you can try:

for elem in elems:
    elem.click()
    print browser.current_url
    browser.back()

edited Jan 7, 2013 at 12:52

answered Jan 7, 2013 at 12:45

root

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4 Comments

user1780952 Over a year ago

Thanks. I don't know why I didn't try that already- no reason why it wouldn't work. I'll give it a run when I get home.

user1780952 Over a year ago

So when I went back the elements were still different, thus I had to 1) count the elements, then 2) Iterate through the range of the element list, and instantiate the list every time because clicking on the i'th element.

user1780952 Over a year ago

for i in driver.find_elements_by_xpath(".//div/div/div[3]/table//tr[12]/td/table//tr/td/a"): list.append(i) count = len(list)-1 print count for i in range(count): print i target = driver.find_elements_by_xpath(".//div/div/div[3]/table//tr[12]/td/table//tr/td/a") print target target[i].click() time.sleep(5) driver.back() time.sleep(5)

Alex Okrushko Over a year ago

@user1780852, if the answer is correct and helpful to you, then you should accept it.

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