Passing multiple variables in a URL

Question

I need help with this. I'm passing two variable through a html link as shown below :

<?php
//loop through the array
foreach ($precost1 as $value): ?>
<ul><li><a name="farmname" href="<?php echo base_url().'uploads/farms/'.$farm;'/'.$value->farmcycle;?>"><?php echo $value->cyclename;?></a></li></ul>
<?php endforeach; ?>

But the link is not working as expected, it ignores the second variable $value->farmcycle any help with the right syntax please?

David Mårtensson · Accepted Answer · 2013-01-22 14:44:43Z

1

.$farm;'/'

The semicolon closes the line, try using . instead.

answered Jan 22, 2013 at 14:44

David Mårtensson

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mychalvlcek · Accepted Answer · 2013-01-22 14:45:53Z

1

semicolon ends php statement, use .(dot) as concat operator

foreach ($precost1 as $value) {
  echo '<ul><li><a name="farmname" href="'.base_url().'uploads/farms/'.$farm.'/'.$value->farmcycle.'">'.$value->cyclename.'</a></li></ul>';    
}

answered Jan 22, 2013 at 14:45

mychalvlcek

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brightintro · Accepted Answer · 2013-01-22 14:46:31Z

1

After $farm you had a ; and forgot to concatentate .

<ul><li><a name="farmname" href="<?php echo base_url().'uploads/farms/'.$farm .'/'.$value->farmcycle;?>"><?php echo $value->cyclename;?></a></li></ul>

answered Jan 22, 2013 at 14:46

brightintro

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Varinder Singh · Accepted Answer · 2013-01-22 14:46:50Z

1

Try this

<?php
//loop through a list of farmnames and create link for each listed farmname
foreach ($precost1 as $value): ?>
    <ul><li><a name="farmname" href="<?php echo base_url().'uploads/farms/'.$farm.'/'.$value->farmcycle;?>"><?php echo $value->cyclename;?></a></li></ul>

<?php endforeach?>

answered Jan 22, 2013 at 14:46

Varinder Singh

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Comments

user1157393 · Accepted Answer · 2013-01-22 15:17:32Z

0

Also, are you sure you want to be creating a <ul> tag for each new item?

Try putting this outside of the foreach, so you are just creating a <li> for each item.

answered Jan 22, 2013 at 15:17

user1157393

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