Bash script and rows

Question

my problem is with rows mysql_query. I need:

Record 0: 2,text is text,3.23

But I have:

Record 0: 2
Record 1: text
Record 2: is
Record 3: text
Record 4: 3.23

Please help me.

results=($(mysql --user root -proot test -Bse "select id,name from Object"));

cnt=${#results[@]}

for (( i=0 ; i<${cnt} ; i++ ))
do
    echo "Record No. $i: ${results[$i]}"

    fieldA=${results[0]};
    fieldB=${results[1]};

done

I don't understand why you're assigning fieldA and fieldB inside the for loop; if you want those to contain certain parts of each record, you shouldn't assign whole records to them. — Costi Ciudatu
– Costi Ciudatu, Commented Feb 18, 2013 at 9:04

dogbane · Accepted Answer · 2013-02-18 09:17:44Z

6

The problem is that you are storing the output of mysql into an array. Now, if mysql returns multiple records you won't know when a record ends and the next one starts because the array will contain the "flattened" data e.g. ( record1_fieldA record1_fieldB record2_fieldA record2_fieldB ... )

Instead, use a while loop to iterate over the records like this:

i=0
while read fieldA fieldB
do
    echo "Record $(( i++ )): fieldA: $fieldA fieldB: $fieldB"
done < <(mysql --user root -proot test -Bse "select id,name from Object")

answered Feb 18, 2013 at 9:17

dogbane

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3 Comments

Unmerciful Over a year ago

but, what when any field is empty? I have: ('aaao-230-27910', 1, 101, '0', '18435', ,); I want: ('','aaao-230-27910', 1, 101, '0', '18435');

Unmerciful Over a year ago

I use it: while read fieldA fieldB fieldC fieldD fieldE fieldF fieldG fieldH fieldI fieldJ$ ... do echo "$INS1 $fieldA, '$fieldB', '$fieldC', $fieldD, $fieldE, $fieldF, $field$ ... done < <(mysql --user root -pnorbert test -Bse "select id, name, description, ....

Unmerciful Over a year ago

And I have problem in Last field. I have two field in one (0 and 23654): ...1, 101, 0 23654);

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