Pointer Arithmetic for String Parsing

So I'm trying to get a grasp of pointers/arrays by creating a basic function, strend, that returns 1 if a substring occurs at the end of a given string and 0 if not. I realize I could accomplish this by measuring the length of a char array, subtracting the length of the substring from that length, and starting my program there, but I kind of want to do it the way my function does it to get a stronger grasp of pointer arithmetic. So here is the program:

#include <stdio.h>
#define NELEMS(x) (sizeof(x) / sizeof(x[0]))

int strend(char *string, char *substring, int substringLength){
    int count; /*keep track of how many number of chars that match in a row*/
    while(*string != '\0'){
        count = 0;
        while(*string == *substring){
            if (count + 1 == substringLength) return 1; /*if matches = length of str*/
            count++; 
            string ++;
            substring ++;
        }
    if (count == 0) string++; /*only increment outer loop if inner loop has done no work*/
    else {
        substring - count; /*reset substring, don't increment string... BUGGY*/
         }
    }
    return 0;
}

int main(){
    char string[] = "John Coltrane";
    char substring[] = "Coltrane";
    int substringLength = NELEMS(substring);
    printf("%d \n", strend(string, substring, substringLength));
    char string2[] = "John Coltrane is Awesome Coltrane";
    char substring2[] = "Coltrane";
    int substringLength2 = NELEMS(substring);
    printf("%d \n", strend(string2, substring2, substringLength2));
    return 1;
}

For the first test strings, string and substring, I get the right result, returning 1 because "Coltrane" is at the end of the string. Similarly, if I take the "Coltrane" out of string2, I get the correct result, returning 0 because the string does not end with Coltrane.

However, for the version of string2 that you see above, I also get zero, and the problem lies in the fact that strend does not reset substring after I iterate over it and increment it while it matches part of the main string. This is fine when the first instance of substring is at the end of the string, but not when there are two instances, as in string2. I thought that substring - count would decrement the pointer back to the beginning of the substring array, but it does not appear to be doing that.

If I change that expression with substring--, it does show the last character of the substring, but is an expression like for(int i = 0; i < count; i++, substring--) really the only way to do this?

Edit: Replacing substring - count with for(; count > 0; count--, substring--) seems like a pretty elegant one liner and it works for me, but I still have a gut feeling there's a better way.