I am trying to pass a struct array to another without success.
s(1).f = (1:3);
s(2).f = (4:6);
s(3).f = (7:9);
q(1).n = 'nameA';
q(2).n = 'nameB';
q(3).n = 'nameC';
q(3).f = [];
q.f = s.f
The field n shouldn't be modified.
Do I miss something?
You can assign each field of an array of structs directly to a cell array and then you can use deal to convert a struct to a cell array:
s(1).f = (1:3);
s(2).f = (4:6);
s(3).f = (7:9);
q(1).n = 'nameA';
q(2).n = 'nameB';
q(3).n = 'nameC';
c = cell(3,1);
[c{:}] = deal(s.f);
[q.f] = c{:};
Here is a good article on this sort of thing
Edit: Or as Shai points out you can just go
[q.f] = s.f
[q.f] = s.f?
dealcommand doesn´t work. The error message is: "The left hand side has c{:} inside brackets, which requires that c be defined, so that the number of expected results can be computed"s.f, which also delivers a comma separated list (CSL). The [] on lhs in combination with a CSL on the rhs is the replacement syntax for deal()command since Matlab version 7.
[q.f] = s.f notation only works if q is preallocated to the correct size. If q has not been previously defined, this approach will only define q as s(1).fHow about arrayfun
q = arrayfun( @(x,y) setfield( x, 'f', y.f ), q, s );
Apparently setfield is only for setting one struct element in struct array -- thus the arrayfun.
EDIT:
a much better answer given by Dan.
fieldnames.I wanted to make this suggestion by Shai more visible because it’s easier to read.
[q.f] = s.f
Though I'd say @Dan's answer is pretty canon for this question, I'd like to present an alternative:
s(1).f = (1:3);
s(2).f = (4:6);
s(3).f = (7:9);
[q(1:length(s)).f] = s.f;
Though slightly more verbose than the [q.f] = s.f syntax, it has the advantage of functioning as expected even if q has not been preallocated to the correct size to be a copy of s.
For example:
s(1).f = (1:3);
s(2).f = (4:6);
s(3).f = (7:9);
[q.f] = s.f;
Returns q.f as a 1x1 struct equal to s(1).f
