What I am trying to do is to extract email address out of the string SomeName, First ([email protected])
Here is the code that I already tried:
var stringToSearchIn="SomeName, First ([email protected])";
var re = /^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
var extractedEmail=re.exec(stringToSearchIn);
The variable extractedEmail in the code returns a null.
I tried this and failed
...is not a very useful description of what happenned. At a guess, the re failed to find a match. An obvious cause for this is the regex you've used here will only match a string which ONLY contains an email address - remove the end anchors (^,$) from the regex and you'll get your email address.
var re = /(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))/;
extractedEmail[0].
No need for a regex here. If the string is always of the format
Name (email)
You can simply use ( as delimiter:
var stringToSearchIn="SomeName, First ([email protected])";
var extractedEmail = stringToSearchIn.substr(stringToSearchIn.indexOf('(') + 1).slice(0, -1);
This one works for me.
var searchInThisString ="SomeName, First ([email protected]) SomeName2, First2 ([email protected])";
var foundEmails =[];
var emailRegex = /(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))/;
var gotcha;
while (match = emailRegex.exec(searchInThisString)){
//-- store in array the found match email
foundEmails.push(match[0]);
//-- remove the found email and continue search if there are still emails
searchInThisString= searchInThisString.replace(match[0],"")
}
alert(foundEmails.join(" "))
gotcha and why is match global?Try this regex
@"^\w+([-+.']\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*$"
This will accept any of the following:
and so on...
(and)as delimiters? No need for a regex then.@example.com.