SyntaxError: syntax error in ajaxFileUpload jquery plugin

Question

i want to pass other parameters with file to save in database.when i put code to get those variables and save in database it give me alert "SyntaxError: syntax error"... here is my code

$.ajaxFileUpload
    ({
    url:'popup/doc_mydeal.php',
    secureuri:false,
    fileElementId:'deals_documents',
    dataType: 'json',
    data:{rand_key: $('#rand_key').val(), document_name: $('#document_name').val()},
    success: function (data, status)
            {
     if(typeof(data.error) != 'undefined')
                {
                if(data.error != '')
                {
                 alert(data.error);
                 }
             }
            },
            error: function (data, status, e)
            {
                alert(e);
            }
        })

Now on doc_mydeal.php

$tempFile = $_FILES['deals_documents']['tmp_name'];
$targetFile=$path.$_REQUEST['rand_key'].basename($_FILES['deals_documents']['name']);
move_uploaded_file($tempFile,$targetFile);

and here is mysql query to save in database

No the same code is working for some time...but some time it give me alert(in javascript) saying "SyntaxError: syntax error" — Methew
– Methew, Commented Mar 6, 2013 at 16:07
@Methew Use the json_encode function rather than trying to generate the correct JSON string yourself. — Anthony Grist
– Anthony Grist, Commented Mar 6, 2013 at 16:09

Anthony Grist · Accepted Answer · 2013-03-06 16:22:41Z

2

When you specify a dataType of json in the options for the jQuery AJAX call you're telling the code that the server will be returning valid JSON. Based on this information jQuery will implicitly parse the response text as JSON, passing the resulting object as the argument of the callback function.

In the case that the response text isn't valid JSON the parse will fail and the error callback will be executed instead. As has been pointed out in the comments, what you're returning from your PHP script is invalid JSON.

answered Mar 6, 2013 at 16:22

Anthony Grist

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2 Comments

Methew Over a year ago

but why my data is not saved in mysql table? formating json and returning it is executed later!!

Methew Over a year ago

i just want to return filename..what i should do on both sides?

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