Getting location address instead of value while printing using pointers with structures?

Question

I have this structure and using pointers , I am trying to print the values of different structure variables , but for int variables it prints location address instead of value and for char variables the result is correct.

#include <stdio.h>
#include <stdlib.h>


struct calc{

    int row;
    int col;
    int menu_name[20];
    int sub_menu_name[20]; 

    };




int main()
{
int count = 0, i = 0;

struct calc *P_calc[2];

//p_calc = (struct calc *)malloc(sizeof(struct calc)*2);


for(count; count<1; count++)
{
      P_calc[count] = (struct calc *)malloc(sizeof(struct calc));

       printf("Please enter the row cordinates: \n");

       scanf("%d",P_calc[i]->row);
       printf("Please enter the col cordinates: \n");

       scanf("%d",P_calc[i]->col);
       printf("Please enter the menu_name: \n");

       scanf("%s",P_calc[i]->menu_name);
       printf("Please enter the sub_menu_name: \n");

       scanf("%s",P_calc[i]->sub_menu_name);


}

   for(i; i<1; i++)  
       {        
        printf("row : %d\n",P_calc[i]->row);

        printf("col :%d\n",P_calc[i]->col);

        printf("menu_name: %s\n",P_calc[i]->menu_name);

        printf("sub_menu_name :%s\n",P_calc[i]->sub_menu_name);
        }


system("PAUSE");
return 0;    
}

Please Help Me.

Thanks in Advance.

Please make a habit of adding actual and desired output and/or comments indicating which lines print what and what they should print. — Bernhard Barker
– Bernhard Barker, Commented Mar 13, 2013 at 5:49
Sorry buddy ...i will follow that next time when i post...thanks for your advice — studyembedded
– studyembedded, Commented Mar 13, 2013 at 5:59

Anthony · Accepted Answer · 2013-03-13 06:16:10Z

3

Here are your problems:

The structure should be

struct calc{

int row;
int col;
char menu_name[20];
char sub_menu_name[20]; 

};

scanf("%d",P_calc[i]->row);should be scanf("%d",&P_calc[i]->row);
scanf("%d",P_calc[i]->col);should be scanf("%d",&P_calc[i]->col);

It is also a good idea to check the return value from scanf.

edited Mar 13, 2013 at 6:16

Anthony

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answered Mar 13, 2013 at 5:50

Ed Heal

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2 Comments

studyembedded Over a year ago

Thanks friend...i am such a stupid that i forgot the basics ...thanks a lot!

Barath Ravikumar Over a year ago

@studyembedded , everyone makes mistakes , thats how learning happens !!

uba · Accepted Answer · 2013-03-13 05:49:37Z

0

The scanf statement should be

scanf("%d",&P_calc[i]->row);

The address needs to be passed to scanf. Similarly while reading the col variable.

answered Mar 13, 2013 at 5:49

uba

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