I don't know whether this is possible or not, but I would like to know if it is and, if so, how it works. So here is my question:
I have 2-3 custom model classes of my own. For example, Customer,
Employee and Product. I also have a class name in a string. Based on the class name, I want to create an instance and return it to a view. How can I achieve this?
I know that one option is an if/else statement, but I would like a better, dynamic way.
Having the class name in string is not enough to be able to create its instance. As a matter of fact you will need full namespace including class name to create an object.
Assuming you have the following:
string className = "MyClass";
string namespaceName = "MyNamespace.MyInternalNamespace";
Than you you can create an instance of that class, the object of class MyNamespace.MyInternalNamespace.MyClass using either of the following techniques:
var myObj = Activator.CreateInstance(namespaceName, className);
or this:
var myObj = Activator.CreateInstance(Type.GetType(namespaceName + "." + className));
Hope this helps, please let me know if not.
string frmName = "frmCustomer";
//WorldCarUI. is the namespace of the form
Type CAType = Type.GetType("WorldCarUI." + frmName );
var myObj = Activator.CreateInstance(CAType);
Form nextForm2 = (Form)myObj;
nextForm2.Show();
this does works..
Regards Avi
the easiest way is to use Activator. Pass class name to GetType and Create new instance.
ClassInstance s1 = (ClassInstance)Activator.CreateInstance(Type.GetType("App.ClassInstance"));
public class ClassInstance
{
public string StringData { get; set; }
}
Regards, Nik
Activator class does this job in .net and this technique is very usefull for dependency injection kind of scenarios.
string NameSpace = "ProjectName.YourNameSpace";
string ProbeClass = "CLassName";
ObjectHandle ProberHandle = Activator.CreateInstance(NameSpace, ProbeClass) as ObjectHandle;
ClassName Prober = ProberHandle.Unwrap() as ClassName;
Ensure that you unwrap before type casting otherwise it will give conversion error.
