Unix Shell scripting: how to modify output file names accordingly

Question

So my current shell scripting is:

for j in *.jpg
do
  tesseract $j $j
done

where tesseract converts jpg files into text files. With this script, if there was a file HAHA.jpg, then the output file name becomes, HAHA.jpg.txt but I want it to be just HAHA.txt

Is there a way to make the output file name as HAHA.txt instead of HAHA.jpg.txt?

chris · Accepted Answer · 2013-03-21 05:43:21Z

2

If you have a shell variable j you can strip a suffix matching a given pattern as follows

${j%%.jpg}

Where %% indicates that the longest matching suffix should be removed and .jpg is the pattern ("a dot, followed by three letters: j, p, and g").

answered Mar 21, 2013 at 5:43

chris

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1 Comment

DavidA Over a year ago

to strip any extension, you can use ${j%%.*}.

Guru · Accepted Answer · 2013-03-21 05:49:01Z

0

Add this line after your tesseract command:

for j in *.jpg
do
  tesseract $j $j
  mv ${j}.txt  ${j/jpg/txt}
done

Even though the tesseract has renamed your file, the variable $j will be containing HAHA.jpg.

answered Mar 21, 2013 at 5:49

Guru

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1 Comment

Sardonic Over a year ago

Thank you ! could you tell me what the ${j/jpg/txt} line does?? I am quite new to shell scripting,, !

perreal · Accepted Answer · 2013-03-21 05:52:03Z

0

Using basename:

for j in *.jpg
do
  tesseract $j $(basename -s .jpg $j)
done

answered Mar 21, 2013 at 5:52

perreal

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