PHP preg_replace expression to remove URL parameter

Question

I wanted to remove all occurrences of specific pattern of a parameter from a URL using preg_expression. Also removing the last "&" if exist The pattern looks like: make=xy ("make" is fixed; "xy" can be any two letters)

Example:

http://example.com/index.php?c=y&make=yu&do=ms&r=k&p=7&

After processing preg_replace, the outcome should be:

http://example.com/index.php?c=y&do=ms&r=k&p=7

I tried using:

$url = "index.php?ok=no&make=ae&make=as&something=no&make=gr";
$url = preg_replace('/(&?lang=..&?)/i', '', $url);

However, this did not work well because I have duplicates of make=xx in the URL (which is a case that could happen in my app).

why are you using lang when you want to replace make ?

Dale
– Dale

2013-04-03 09:11:35 +00:00
Commented Apr 3, 2013 at 9:11 — Dale
– Dale, Commented Apr 3, 2013 at 9:11
sorry that lang meant to be make.

mimidov
– mimidov

2013-04-03 09:16:34 +00:00
Commented Apr 3, 2013 at 9:16 — mimidov
– mimidov, Commented Apr 3, 2013 at 9:16

HamZa · Accepted Answer · 2013-04-03 09:25:58Z

8

You don't need RegEx for this:

$url = "http://example.com/index.php?ok=no&make=ae&make=as&something=no&make=gr&";

list($file, $parameters) = explode('?', $url);
parse_str($parameters, $output);
unset($output['make']); // remove the make parameter

$result = $file . '?' . http_build_query($output); // Rebuild the url
echo $result; // http://example.com/index.php?ok=no&something=no

answered Apr 3, 2013 at 9:25

HamZa

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Comments

Peter Adrian · Accepted Answer · 2013-04-03 09:39:20Z

2

You could try using:

$str = parse_url($url, PHP_URL_QUERY);
$query = array();
parse_str($str, $query);
var_dump($query);

This will return to you the query as an array. You could then use http_build_query() function to restore the array in a query string.

But if you want to use regexp:

$url = "index.php?make=ae&ok=no&make=ae&make=as&something=no&make=gr";
echo $url."\n";
$url = preg_replace('/\b([&|&amp;]{0,1}make=[^&]*)\b/i','',$url);
$url = str_replace('?&','?',$url);
echo $url;

This will remove all make in the URL

edited Apr 3, 2013 at 9:39

answered Apr 3, 2013 at 9:24

Peter Adrian

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2 Comments

mimidov Over a year ago

both ways didn't work for me. the first way returned NULL and the second one returned strange output

Peter Adrian Over a year ago

I edited the post, in my test, the regex works well. In the first way, i forgot that parse_str has the array passed by reference, and does not return it.

mohammad mohsenipur · Accepted Answer · 2013-04-03 09:13:01Z

0

with rtrim you can remove last &

$url = rtrim("http://example.com/index.php?c=y&make=yu&do=ms&r=k&p=7&","&");
$url = preg_replace('~&make=([a-z\-]*)~si', '', $url);

answered Apr 3, 2013 at 9:13

mohammad mohsenipur

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1 Comment

mimidov Over a year ago

if make comes directly after index.php?, it is not replaced. Also the values of all make='s are not removed as well

Dale · Accepted Answer · 2013-04-03 09:13:31Z

0

$url = "index.php?ok=no&make=ae&make=as&something=no&make=gr";
$url = preg_replace('/(&?make=[a-z]{2})/i', '', $url);
echo $url;

answered Apr 3, 2013 at 9:13

Dale

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1 Comment

mimidov Over a year ago

if $url = "index.php?make=xx&ok=no" .. the outcome will leave extra & after index? .. which is not correct

Mannu · Accepted Answer · 2019-07-17 05:51:25Z

0

Just by using preg_replace

$x = "http://example.com/index.php?c1=y&make=yu&do1=ms&r1=k&p1=7&";

$x = preg_replace(['/(\?make=[a-z]*[&])/i', '/(\&make=[a-z]*[^(&*)])/i', '/&(?!\w)/i'], ['?','',''], $x);
echo $x;

And the result is: http://example.com/index.php?c1=y&do1=ms&r1=k&p1=7

Hope this will be helpful to you guys.

answered Jul 17, 2019 at 5:51

Mannu

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