Creating a Java Script Array from hidden values

Question

var a1=$("#orderprogress").val().toFixed(2);//a1=50
var a2=$("#poprogress").val().toFixed(2); //a2=70

if i want to create a array like this how would i do it?

graphData = new Array(
             [a1 value,'#222222'],//[50,'#222222']
             [a2 value ,'#7D252B']//[70,'#222222']
        );

I think this is an okay question. The user has an issue, has tried something, and has shown code. It might be a trivial fix, but it's still an okay question. — Jazzepi
– Jazzepi, Commented Apr 12, 2013 at 19:33

Ian · Accepted Answer · 2013-04-16 20:16:15Z

4

Try using the following code:

var a1 = +(+$("#orderprogress").val()).toFixed(2);
var a2 = +(+$("#poprogress").val()).toFixed(2);

graphData = [
    [a1, '#222222'],//[50,'#222222']
    [a2, '#7D252B']//[70,'#222222']
];

DEMO: http://jsfiddle.net/ERccS/4/

This will take the textbox value (a string), convert it to a number, call toFixed(2) on it, then convert it back to a number.

Unfortunately (if you care), "50" will be displayed as 50 (this happens with trailing 0s). If you always need 2 decimal places no matter what, take off the first + I have in my code - they will be kept as strings and always have 2 decimal places.

I'm not exactly sure what you're looking to do with the toFixed. The .val() method always returns a string. toFixed isn't a String method - it's a Number method. And its result is the original Number rounded to a certain number of decimal places (what you pass to the method). In your case, it's 2.

edited Apr 16, 2013 at 20:16

answered Apr 12, 2013 at 19:29

Ian

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4 Comments

user1507789 Over a year ago

I'm fetching data from server and setting the decimal precision to 2 . My string value is 50.0123123 so I'm reducing it to 50.01

Ian Over a year ago

@user1507789 Sounds good, then yeah, you'll have to use my code above for setting a1 and a2

Rajaprabhu Aravindasamy Over a year ago

.toFixed(2) returns a string. check jsfiddle.net/ERccS/1. you have to cast again to get the result as number. By the way you had given an explanation toFixed isn't a String method - it's a Number method

Ian Over a year ago

@RajaprabhuAravindasamy Thanks for pointing that out. I forgot that the result was expected to be a number. And I'm not sure what you meant by "By the way you had given an explanation toFixed isn't a String method - it's a Number method"

PurkkaKoodari · Accepted Answer · 2013-04-12 19:30:43Z

2

graphData = [[a1, '#222222'], [a2, '#7D252B']];

answered Apr 12, 2013 at 19:30

PurkkaKoodari

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Comments

Jazzepi · Accepted Answer · 2013-04-12 19:32:28Z

2

Either

var graphData = new Array(new Array(a1,'#222222'),new Array(a2 ,'#7D252B'));

OR

var graphData = [[a1,'#222222'],[a2,'#7D252B']];

answered Apr 12, 2013 at 19:32

Jazzepi

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Comments

Rajaprabhu Aravindasamy · Accepted Answer · 2013-04-12 19:39:57Z

0

try this,

var xArray=[];

var a1=$("#orderprogress").val().toFixed(2);//a1=50
var a2=$("#poprogress").val().toFixed(2); //a2=70

InsertIntoArray(a1,'#fff')
InsertIntoArray(a2,'#fff')

function InsertIntoArray(x,y)
{
var yArray=[x,y];

xArray.push(yArray);

}

or simply,

   var xArray=[];

    var a1=$("#orderprogress").val().toFixed(2);//a1=50
    var a2=$("#poprogress").val().toFixed(2); //a2=70

    xArray.push([a1,"#fff"],[a2,"#fff"]);

edited Apr 12, 2013 at 19:39

answered Apr 12, 2013 at 19:31

Rajaprabhu Aravindasamy

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2 Comments

Ted Hopp Over a year ago

The InsertIntoArray function seems pointless. Just use xArray.push([a1, '#fff']), etc.

Rajaprabhu Aravindasamy Over a year ago

@TedHopp i just thought that, this would be a cleaner way of doing this, Any way thanks for your attention. :)

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