Check if one date is between two dates

Question

I need to check if a date - a string in dd/mm/yyyy format - falls between two other dates having the same format dd/mm/yyyy

I tried this, but it doesn't work:

var dateFrom = "02/05/2013";
var dateTo = "02/09/2013";
var dateCheck = "02/07/2013";

var from = Date.parse(dateFrom);
var to   = Date.parse(dateTo);
var check = Date.parse(dateCheck );

if((check <= to && check >= from))      
    alert("date contained");

I used debugger and checked, the to and from variables have isNaN value. Could you help me?

Daniel, you need to update the corrrect answer. The answer with more votes doesn't check for dates only for months — user3109233
– user3109233, Commented Aug 24, 2018 at 6:26

Chuck · Accepted Answer · 2018-12-20 16:46:41Z

145

Date.parse supports the format mm/dd/yyyy not dd/mm/yyyy. For the latter, either use a library like moment.js or do something as shown below

var dateFrom = "02/05/2013";
var dateTo = "02/09/2013";
var dateCheck = "02/07/2013";

var d1 = dateFrom.split("/");
var d2 = dateTo.split("/");
var c = dateCheck.split("/");

var from = new Date(d1[2], parseInt(d1[1])-1, d1[0]);  // -1 because months are from 0 to 11
var to   = new Date(d2[2], parseInt(d2[1])-1, d2[0]);
var check = new Date(c[2], parseInt(c[1])-1, c[0]);

console.log(check > from && check < to)

edited Dec 20, 2018 at 16:46

Chuck

2585 silver badges13 bronze badges

answered Apr 18, 2013 at 10:36

Diode

25.2k8 gold badges43 silver badges52 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

RobG Over a year ago

+1 for correctly parsing the date string and not leaving it up to an implementation dependent parser.

Onur Yıldırım Over a year ago

Consider db conventions, first date should be inclusive. e.g. check >= from && check < to

chudasamachirag Over a year ago

@Diode check :02/23/2018 from:11/20/2018 to:12/31/2018 it returns true.

Diode Over a year ago

@chudasamachirag: The question was about parsing dd/mm/yyyy format. These dates are in mm/dd/yyyy format

Or Arbel · Accepted Answer · 2016-06-12 01:45:06Z

84

Instead of comparing the dates directly, compare the getTime() value of the date. The getTime() function returns the number of milliseconds since Jan 1, 1970 as an integer-- should be trivial to determine if one integer falls between two other integers.

Something like

if((check.getTime() <= to.getTime() && check.getTime() >= from.getTime()))      alert("date contained");

edited Jun 12, 2016 at 1:45

Or Arbel

2,9652 gold badges31 silver badges40 bronze badges

answered Apr 18, 2013 at 10:26

Jasmine Howell

8715 silver badges4 bronze badges

3 Comments

Bergi Over a year ago

NaN neither has a GetTime nor a getTime method?

Sayan Over a year ago

It will perfectly be working when date format is like - 02/05/2013 but when date is in iso format(date+time) like - 2019-09-12T13:02:14.291Z then use the setHours method before compare dates, Ex -

let compareDate = new Date('checkDate').setHours(0, 0, 0, 0);  let startDate = new Date('startDate').setHours(0, 0, 0, 0);  let endDate = new Date('endDate').setHours(0, 0, 0, 0);  console.log(compareDate <= endDate && compareDate >= startDate);

Hope it will help others :)

Ananda Prasad Bandaru Over a year ago

@SayanSamanta: Your solution is simple & it works. Thanks. Note for others: Time is not checked here.

Chuck · Accepted Answer · 2018-12-20 16:35:45Z

25

Try what's below. It will help you...

Fiddle : http://jsfiddle.net/RYh7U/146/

Script :

if(dateCheck("02/05/2013","02/09/2013","02/07/2013"))
    alert("Availed");
else
    alert("Not Availed");

function dateCheck(from,to,check) {

    var fDate,lDate,cDate;
    fDate = Date.parse(from);
    lDate = Date.parse(to);
    cDate = Date.parse(check);

    if((cDate <= lDate && cDate >= fDate)) {
        return true;
    }
    return false;
}

edited Dec 20, 2018 at 16:35

Chuck

2585 silver badges13 bronze badges

answered Apr 18, 2013 at 10:46

Pandian

9,1562 gold badges26 silver badges34 bronze badges

5 Comments

Pandian Over a year ago

@Bergi: If the Date is NAN then this function return False So the Date you check Or Pass is Not Availed or In Valid and this is the HELL difference between the code of mine and him

Bergi Over a year ago

But the OP's if-condition does that as well? And the question was about the date being NaN in the first place (which it is not in all browsers)

Si8 Over a year ago

What if I wanted to check if now falls under 7:00am to 9:00pm

Bhavin Rana Over a year ago

dateCheck("20/01/2015","22/01/2015","21/02/2015") this case doesnt work

Mike Over a year ago

@BhavinRana This case does not work because you use dd/mm/yyyy - correct would be mm/dd/yyyy

Andrew Mykhalchuk · Accepted Answer · 2019-12-24 13:59:04Z

12

Simplified way of doing this based on the accepted answer.

In my case I needed to check if current date (Today) is pithing the range of two other dates so used newDate() instead of hardcoded values but you can get the point how you can use hardcoded dates.


var currentDate = new Date().toJSON().slice(0,10);
var from = new Date('2020/01/01');
var to   = new Date('2020/01/31');
var check = new Date(currentDate);

console.log(check > from && check < to);

answered Dec 24, 2019 at 13:59

Andrew Mykhalchuk

4341 gold badge4 silver badges12 bronze badges

2 Comments

Ulugbek Over a year ago

this code does not work in safari

Andrew Mykhalchuk Over a year ago

@Ulugbek just tested in latest Safari 15.6 and it's working. Here's a test link - codepen.io/andrew_mykhalchuk/pen/gOejKpW

user3109233 · Accepted Answer · 2017-05-05 21:55:19Z

The answer that has 50 votes doesn't check for date in only checks for months. That answer is not correct. The code below works.

var dateFrom = "01/08/2017";
var dateTo = "01/10/2017";
var dateCheck = "05/09/2017";

var d1 = dateFrom.split("/");
var d2 = dateTo.split("/");
var c = dateCheck.split("/");

var from = new Date(d1);  // -1 because months are from 0 to 11
var to   = new Date(d2);
var check = new Date(c);

alert(check > from && check < to);

This is the code posted in another answer and I have changed the dates and that's how I noticed it doesn't work

var dateFrom = "02/05/2013";
var dateTo = "02/09/2013";
var dateCheck = "07/07/2013";

var d1 = dateFrom.split("/");
var d2 = dateTo.split("/");
var c = dateCheck.split("/");

var from = new Date(d1[2], parseInt(d1[1])-1, d1[0]);  // -1 because months are from 0 to 11
var to   = new Date(d2[2], parseInt(d2[1])-1, d2[0]);
var check = new Date(c[2], parseInt(c[1])-1, c[0]);


alert(check > from && check < to);

KARTHIKEYAN.A · Accepted Answer · 2019-08-11 19:15:42Z

3

I have created customize function to validate given date is between two dates or not.

var getvalidDate = function(d){ return new Date(d) }

function validateDateBetweenTwoDates(fromDate,toDate,givenDate){
    return getvalidDate(givenDate) <= getvalidDate(toDate) && getvalidDate(givenDate) >= getvalidDate(fromDate);
}

answered Aug 11, 2019 at 19:15

KARTHIKEYAN.A

20.5k11 gold badges139 silver badges151 bronze badges

Comments

Nate May · Accepted Answer · 2018-09-26 01:07:10Z

1

Here is a Date Prototype method written in typescript:

Date.prototype.isBetween = isBetween;
interface Date { isBetween: typeof isBetween }
function isBetween(minDate: Date, maxDate: Date): boolean {
  if (!this.getTime) throw new Error('isBetween() was called on a non Date object');
  return !minDate ? true : this.getTime() >= minDate.getTime()
    && !maxDate ? true : this.getTime() <= maxDate.getTime();
};

answered Sep 26, 2018 at 1:07

Nate May

4,0717 gold badges40 silver badges92 bronze badges

Comments

Rafael Sequeira · Accepted Answer · 2019-02-09 22:39:11Z

I did the same thing that @Diode, the first answer, but i made the condition with a range of dates, i hope this example going to be useful for someone

e.g (the same code to example with array of dates)

var dateFrom = "02/06/2013";
var dateTo = "02/09/2013";

var d1 = dateFrom.split("/");
var d2 = dateTo.split("/");

var from = new Date(d1[2], parseInt(d1[1])-1, d1[0]);  // -1 because months are from 0 to 11
var to   = new Date(d2[2], parseInt(d2[1])-1, d2[0]); 



var dates= ["02/06/2013", "02/07/2013", "02/08/2013", "02/09/2013", "02/07/2013", "02/10/2013", "02/011/2013"];

dates.forEach(element => {
   let parts = element.split("/");
   let date= new Date(parts[2], parseInt(parts[1]) - 1, parts[0]);
        if (date >= from && date < to) {
           console.log('dates in range', date);
        }
})

Miyas Mohammed · Accepted Answer · 2020-10-23 05:38:54Z

Suppose for example your date is coming like this & you need to install momentjs for advance date features.

let cmpDate = Thu Aug 27 2020 00:00:00 GMT+0530 (India Standard Time)

    let format = "MM/DD/YYYY";
    let startDate: any = moment().format(format);
    let endDate: any = moment().add(30, "days").format(format);
    let compareDate: any = moment(cmpDate).format(format);
    var startDate1 = startDate.split("/");
    var startDate2 = endDate.split("/");
    var compareDate1 = compareDate.split("/");

    var fromDate = new Date(startDate1[2], parseInt(startDate1[1]) - 1, startDate1[0]);
    var toDate = new Date(startDate2[2], parseInt(startDate2[1]) - 1, startDate2[0]);
    var checkDate = new Date(compareDate1[2], parseInt(compareDate1[1]) - 1, compareDate1[0]);

    if (checkDate > fromDate && checkDate < toDate) {
      ... condition works between current date to next 30 days
    }

Doodl · Accepted Answer · 2017-10-19 09:35:09Z

Try this:

HTML

<div id="eventCheck"></div>

JAVASCRIPT

// ----------------------------------------------------//
// Todays date
var today = new Date();
var dd = today.getDate();
var mm = today.getMonth()+1; //January is 0!
var yyyy = today.getFullYear();

// Add Zero if it number is between 0-9
if(dd<10) {
    dd = '0'+dd;
}
if(mm<10) {
    mm = '0'+mm;
}

var today = yyyy + '' + mm + '' + dd ;


// ----------------------------------------------------//
// Day of event
var endDay = 15; // day 15
var endMonth = 01; // month 01 (January)
var endYear = 2017; // year 2017

// Add Zero if it number is between 0-9
if(endDay<10) {
    endDay = '0'+endDay;
} 
if(endMonth<10) {
    endMonth = '0'+endMonth;
}

// eventDay - date of the event
var eventDay = endYear + '/' + endMonth + '/' + endDay;
// ----------------------------------------------------//



// ----------------------------------------------------//
// check if eventDay has been or not
if ( eventDay < today ) {
    document.getElementById('eventCheck').innerHTML += 'Date has passed (event is over)';  // true
} else {
    document.getElementById('eventCheck').innerHTML += 'Date has not passed (upcoming event)'; // false
}

Fiddle: https://jsfiddle.net/zm75cq2a/

Commodore64 · Accepted Answer · 2022-10-01 23:58:17Z

0

This may feel a bit more intuitive. The parameter is just a valid date string. This function returns true if the date passed as argument is in the current week, or false if not.

function isInThisWeek(dateToCheck){
// Create a brand new Date instance
const WEEK = new Date()

// create a date instance with the function parameter 
//(format should be like dd/mm/yyyy or any javascript valid date format )
const DATEREF = new Date(dateToCheck)

// If the parameter is a not a valid date, return false
if(DATEREF instanceof Date && isNaN(DATEREF)){ 
  console.log("invalid date format")
  return false}

// Get separated date infos (the date of today, the current month and the current year) based on the date given as parameter
const [dayR, monthR, yearR] = [DATEREF.getDate(), DATEREF.getMonth(), DATEREF.getFullYear()]

// get Monday date by substracting the day index (number) in the week from the day value (count) 
//in the month (like october 15th - 5 (-> saturday index)) and +1 because 
//JS weirdly starts the week on sundays
const monday = (WEEK.getDate() - WEEK.getDay()) + 1

// get Saturday date
const sunday = monday + 6

// Start verification
if (yearR !== WEEK.getFullYear())  { console.log("WRONG YEAR"); return false }
if (monthR !== WEEK.getMonth()) { console.log("WRONG MONTH"); return false }
if(dayR >= monday && dayR <= sunday) { return true }
else {console.log("WRONG DAY"); return false}

}

edited Oct 1, 2022 at 23:58

answered Sep 13, 2022 at 15:35

Commodore64

1207 bronze badges

2 Comments

Tobias Schäfer Over a year ago

Hi @Wilfried. could you please format your code to explain the solution you are providing. Currently the answer dooes not look working properly. Thank you!

Commodore64 Over a year ago

I'll do so. @TobiasSchäfer But what's not working properly ?

Md Faizi · Accepted Answer · 2023-04-03 19:09:23Z

0

This will work in all cases.

var curr = new Date("12/01/2023"); // get current date
console.log("curr.getDate()",curr.getDate());
console.log("curr.getDay()",curr.getDay());
var first = curr.getDate() - (curr.getDay()-1); //-1to make monday first day.
console.log(first)
var firstday = new Date(curr.setDate(first)); // 
console.log("first date",firstday)
var firstDay_no=firstday.getDate();
console.log("firstDay_no",firstDay_no)
var last = firstDay_no+ 6; // last day is the first day no + 6
console.log("last",last)
var lastday = new Date(curr.setDate(last)); //

console.log("last date",lastday)

edited Apr 3, 2023 at 19:09

answered Apr 3, 2023 at 19:08

Md Faizi

11 bronze badge

Comments

user2292370 · Accepted Answer · 2023-11-01 10:30:24Z

0

const dateFrom = new Date(new Date().getFullYear(), 11, 1); 
const dateTo = new Date(new Date().getFullYear() + 1, 0, 6);

const dateCheck = new Date("02/07/2013");

const isBetween = dateCheck >= dateFrom && dateCheck <= dateTo;

console.log('is date in range?', isBetween);

answered Nov 1, 2023 at 10:30

user2292370

611 silver badge3 bronze badges

Comments

Praveen Kumar · Accepted Answer · 2024-09-24 08:36:22Z

Check if date is available in the range within plain time. below are examples: if today now is 24-09-2024 and time is 11:00 AM, then below values are:

0-1 > between 24-09-2024 00:00:00 and current time.
1-2 > between 23-09-2024 00:00:00 and 24-09-2024 00:00:00
2-3 > between 22-09-2024 00:00:00 and 23-09-2024 00:00:00

const start = this.goBackByDays(DaysAgoFrom);
const end = this.goBackByDays(daysAgoTo);
const dateToCheck = Date.parse(this.responseData[0].sent);
this.presentOrNot = DaysAgoFrom
  ? dateToCheck >= start && dateToCheck <= end
  : dateToCheck <= end;

    goBackByDays(days: number) {
      const startDate = new Date();
      startDate.setDate(startDate.getDate() - Math.abs(days ? days - 1 : 0));
      days != 0 ? startDate.setHours(0, 0, 0, 0) : null;
      console.log(startDate.toString());
      return Date.parse(startDate.toString());
    }

https://stackblitz.com/edit/angular-v7b4kd?file=src%2Fapp%2Fapp.component.ts

Lal krishnan S L · Accepted Answer · 2014-05-09 11:54:31Z

-1

Try this

var gdate='01-05-2014';
        date =Date.parse(gdate.split('-')[1]+'-'+gdate.split('-')[0]+'-'+gdate.split('-')[2]);
        if(parseInt(date) < parseInt(Date.now()))
        {
            alert('small');
        }else{
            alert('big');
        }

Fiddle

answered May 9, 2014 at 11:54

Lal krishnan S L

1,7451 gold badge16 silver badges33 bronze badges

Comments

pravindot17 · Accepted Answer · 2022-06-09 20:40:36Z

-1

This question is very generic, hence people who are using date libraries also check for the answer, but I couldn't find any answer for the date libraries, hence I am posting the answer for Luxon users.

const fromDate = '2022-06-01T00:00:00.000Z';
const toDate = '2022-06-30T23:59:59.999Z';
const inputDate = '2022-08-09T20:26:13.380Z';

if (
  DateTime.fromISO(inputDate) >= DateTime.fromISO(fromDate) &&
  DateTime.fromISO(inputDate) <= DateTime.fromISO(toDate)
) {
  console.log('within range');
} else {
  console.log('not in range');
}

answered Jun 9, 2022 at 20:40

pravindot17

1,2831 gold badge19 silver badges33 bronze badges

Collectives™ on Stack Overflow

Check if one date is between two dates

16 Answers 16

4 Comments

3 Comments

5 Comments

2 Comments

Comments

Comments

Comments

Comments

Comments

Comments

2 Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

16 Answers 16

4 Comments

3 Comments

5 Comments

2 Comments

Comments

Comments

Comments

Comments

Comments

Comments

2 Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related