Parse Integer error

Question

For some reason I cant get a string number value to convert to an integer the error I get is run:

Exception in thread "main" java.lang.NumberFormatException: For input string: "6327818260"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:495)
    at java.lang.Integer.parseInt(Integer.java:527)
    at MyDirectory.getsize(MyDirectory.java:18)
    at a19010.main(a19010.java:79)

Java Result: 1

If my input string is "6327818260" why can't it become an integer? my code is

public String getsize()
{
  int intSize = Integer.parseInt(mySize);
  int count = 0;
  String dataType = "";
  while (intSize > 1000)
  {   
   intSize = intSize / 1000;
   count++;
  } 
  switch (count)
  {
    case 0:
    dataType = "Bytes";
    break;
    case 1:
    dataType = "KB";
    break;
    case 2:
    dataType = "MB";
    break;
    case 3:
    dataType = "GB";
    break;
    case 4:
    dataType = "KB";
    break;    
  }   
    return intSize + dataType ;
}

mySize is taken from part of a string gotten from a text file here

 public class MyDirectory 
{
  String myName = "" ;
  String myNum = "";
  String mySize = "";
    public MyDirectory(String line)

  {
    line = line.trim();  
    String[] lineParts = line.split(" ");
     mySize = lineParts[0];
     myNum = lineParts[1];
     myName = lineParts[3];
  }

The line im splitting looks like 6327818260 6486 SUB-TOTAL: E:\WIS26\LCORRES

What is the maximum value of an Integer?

peter.murray.rust
– peter.murray.rust

2013-04-19 20:16:10 +00:00
Commented Apr 19, 2013 at 20:16 — peter.murray.rust
– peter.murray.rust, Commented Apr 19, 2013 at 20:16

Affe · Accepted Answer · 2013-04-19 20:29:56Z

6

The largest possible integer is 2147483647 which is a good deal less than the value you're trying to parse: 6327818260

You will need to use a long or a BigInteger/BigDecimal to hold that value.

For BigInteger/BigDecimal Strings representing base 10 integers can be parsed by the constructors that take a string argument.

BigDecimal bigDecimal = new BigDecimal("6327818260");

edited Apr 19, 2013 at 20:29

answered Apr 19, 2013 at 20:16

Affe

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4 Comments

Alex Chapp Over a year ago

Is there a method to turn a string into a big decimal? Im have trouble initializing the big decimal from the mySize string

Affe Over a year ago

The constructor that takes a String understands decimal integers.

Alex Chapp Over a year ago

That's what I thought I must be doing something incorrectly my constructor looks like BigDecimal size = BigDecimal(mySize);

Alex Chapp Over a year ago

That fixed it of corse. I guess I forgot for some reason

Kent · Accepted Answer · 2013-04-19 20:17:38Z

2

6327818260 is greater than the Integer.MAX_VALUE `2147483647`

You can try to parse the string to Long

answered Apr 19, 2013 at 20:17

Kent

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2 Comments

Alex Chapp Over a year ago

This lets my code compile but It doesn't work for the division since it get rid of the decimal

Kent Over a year ago

if it is decimal, try BigDecimal. you can BigDecimal dc = new BigDecimal(str);

John · Accepted Answer · 2013-04-19 20:16:48Z

0

If it's a 32-bit integer you're looking to pack that into, it's too big.

answered Apr 19, 2013 at 20:16

John

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