Python Parse lines of input file

Question

Im a recent graduate who has made some contacts and trying to help one with a project. This project will help evolve into something open source for people. So any help I can get would be greatly appreciated.

Im trying to parse out certain items in a file I have succeeded in parsing out the specific items. I now need to figure out how to attach all the remaining data to another variable in an organized way for example.

file=open("file.txt",'r') 

row = file.readlines()

for line in row:
    if line.find("Example") > -1:
        info = line.split()
        var1 = info[0]
        var2 = info[1]
        var3 = info[2]
        remaining_data = ????

^^^^^^^^^^is my sample code already doing 90% of what i need. I want to get the remaining_data to all go into that variable line by line for.

print remaining_data

output:remaining_data{
    line 1 of data
    line 2 of data
    line 3 of data
    line 4 of data
}

how can I get it organized and going in like that line by line?

cmd · Accepted Answer · 2013-04-22 20:18:38Z

7

remaining_data = []
for line in open("file.txt",'r'):
    if line.find("Example") > -1:
        info = line.split()
        var1 = info[0]
        var2 = info[1]
        var3 = info[2]
        remaining_data.append(' '.join(info[3:]))

at the end of the loop, remaining data will have all lines with out the first 3 elements

answered Apr 22, 2013 at 20:18

cmd

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Meitham · Accepted Answer · 2013-04-22 19:56:14Z

1

by using a slice

remaining_data=info[3:]

If you need the indices you could do

for i, line in enumerate(info[3:]):
    print("{}: {}".format(i, line))

answered Apr 22, 2013 at 19:56

Meitham

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