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i have string which is separated by "." when i try to split it by the dot it is not getting spitted.

Here is the exact code i have. Please let me know what could cause this not to split the string.

public class TestStringSplit {
    public static void main(String[] args) {
        String testStr = "[Lcom.hexgen.ro.request.CreateRequisitionRO;";
        String test[] = testStr.split(".");
        for (String string : test) {
            System.out.println("test : " + string);
        }
        System.out.println("Str Length : " + test.length);
    }
}

I have to separate the above string and get only the last part. in the above case it is CreateRequisitionRO not CreateRequisitionRO; please help me to get this.

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  • i get the last value like System.out.println("Last Value : " + test[test.length-1]); it also prints the last one as CreateRequisitionRO; but what i want is CreateRequisitionRO how to get this Commented Apr 24, 2013 at 6:23
  • 1
    see my answer. second part. Commented Apr 24, 2013 at 6:38
  • possible duplicate of The split() method in Java does not work on a dot (.) Commented Apr 24, 2013 at 16:06

7 Answers 7

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5

You can split this string through StringTokenizer and get each word between dot

StringTokenizer tokenizer = new StringTokenizer(string, ".");
String firstToken = tokenizer.nextToken();
String secondToken = tokenizer.nextToken();

As you are finding for last word CreateRequisitionRO you can also use

String testStr = "[Lcom.hexgen.ro.request.CreateRequisitionRO;";
String yourString = testStr.substring(testStr.lastIndexOf('.')+1, testStr.length()-1);
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4 
String testStr = "[Lcom.hexgen.ro.request.CreateRequisitionRO;";
String test[] = testStr.split("\\.");
for (String string : test) {
    System.out.println("test : " + string);
}
System.out.println("Str Length : " + test.length);

The "." is a regular expression wildcard you need to escape it.

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3

Change String test[] = testStr.split("."); to String test[] = testStr.split("\\.");.

As the argument to String.split takes a regex argument, you need to escape the dot character (which means wildcard in regex):

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3

Note that String.split takes in a regular expression, and . has special meaning in regular expression (which matches any character except for line separator), so you need to escape it:

String test[] = testStr.split("\\.");

Note that you escape the . at the level of regular expression once: \., and to specify \. in a string literal, \ needs to be escaped again. So the string to pass to String.split is "\\.".

Or another way is to specify it inside a character class, where . loses it special meaning:

String test[] = testStr.split("[.]");
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2

You need to escape the . as it is a special character, a full list of these is available. Your split line needs to be:

String test[] = testStr.split("\\.");
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1

Split takes a regular expression as a parameter. If you want to split by the literal ".", you need to escape the dot because that is a special character in a regular expression. Try putting 2 backslashes before your dot ("\\.") - hopefully that does what you are looking for.

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1 
String test[] = testStr.split("\\.");
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