php notice array to string conversion [closed]

Question

I have an error with my function.

Notice: Array to string conversion in....

Just I wanna check array availability & return if have. I have searched but, I can't do.

Here is my function:

function if_array_exists($array,$value) {
    if(isset($array[$value]) || array_key_exists($value,$array)) {
        $result=array();
        $result[0]=$value;
        return $result;
    } else {
        return '<!--- no array named as '.$value.' value in ---!>';
    }
}

You're probably passing in a string as the $array parameter. Check the calling code and see what arguments you're passing in — Bojangles
– Bojangles, Commented Apr 28, 2013 at 19:53
debug your code. start with looking at the line that is causing the error. then check what you are passing to the function etc, as @Bojangles suggested! — michi
– michi, Commented Apr 28, 2013 at 19:57

jerdiggity · Accepted Answer · 2013-04-28 20:02:52Z

2

If you check to see if it's an actual array first, that should prevent the notice (because it will skip directly to the else.

function if_array_exists($array,$value) {
    if(is_array($array) && (isset($array[$value]) || array_key_exists($value,$array))) {
        $result=array();
        $result[0]=$value;
        return $result;
     } else {
        return '<!--- no array named as '.$value.' value in ---!>';
    }
}

answered Apr 28, 2013 at 20:02

jerdiggity

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1 Comment

liveth19937 Over a year ago

Thanks. I have solved problem with this function: paste2.org/pXkLwDGI

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