add new line to output file python

Question

hi i want to write the newline character to an output file so here is my code:

a=['\n:001000', '\r:10111', ' :000', '!:01101111101', '":0010011', "':0010010110", '(:00100101111110110', '):00100101111110111', ',:101100', '-:1011011011', '.:0100100', '0:011011111001101', '1:0110111110010', '2:1011011000111', '3:011011111001110']

text_file = open("Output.txt", "wb")
    for t in a:
        text_file.write(t+" ")

but my output is not what i expected:

:001000  :10111   :000  !:01101111101  ":0010011  ':0010010110  (:00100101111110110  ):00100101111110111  ,:101100  -:1011011011  .:0100100  0:011011111001101  1:0110111110010  2:1011011000111  3:011011111001110

does anyone know how to actually write the newline character to the output ???

i want something like eg: \n:001000 \r:10111 etc

Writing the newline character is as simple as appending "\n" or '\n' to the print statement as @Michel pointed out. Furthermore, the '\r' carriage return works, look at the file in a text editor! Could you please try and more accurately phrase your intentions? What was unexpected about the output you got? Is it the same in the file? What should it have looked like? — HennyH
– HennyH, Commented May 1, 2013 at 8:43

jamylak · Accepted Answer · 2013-05-01 08:26:22Z

1

You are printing those characters, just look at the repr

>>> a=['\n:001000 ', '\r:10111 ', ' :000 ', '!:01101111101 ', '":0010011 ', "':0010010110 ", '(:00100101111110110 ', '):00100101111110111 ', ',:101100 ', '-:1011011011 ', '.:0100100 ', '0:011011111001101 ', '1:0110111110010 ', '2:1011011000111 ', '3:011011111001110 ']
>>> with open("Output.txt", "wb") as f:
        for t in a:
            f.write(t + " ")


>>> with open("Output.txt", "rb") as f:
        print repr(f.read()) # representation


'\n:001000  \r:10111   :000  !:01101111101  ":0010011  \':0010010110  (:00100101111110110  ):00100101111110111  ,:101100  -:1011011011  .:0100100  0:011011111001101  1:0110111110010  2:1011011000111  3:011011111001110  '

Or maybe you are asking to escape those characters to print them raw:

>>> with open("Output.txt", "wb") as f:
        for t in a:
            f.write((t + " ").encode('string_escape'))


>>> with open("Output.txt", "rb") as f:
        print f.read()


\n:001000  \r:10111   :000  !:01101111101  ":0010011  \':0010010110  (:00100101111110110  ):00100101111110111  ,:101100  -:1011011011  .:0100100  0:011011111001101  1:0110111110010  2:1011011000111  3:011011111001110

answered May 1, 2013 at 8:26

jamylak

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2 Comments

Tommy Over a year ago

i just wish to read the first line as there are other things after that first line that i dont put it on the question cause i just stuck at that question

jamylak Over a year ago

@TommyNgo To read the first line change .read to .readline

Michel Keijzers · Accepted Answer · 2013-05-01 08:21:34Z

0

The new line character is '\n'

answered May 1, 2013 at 8:21

Michel Keijzers

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3 Comments

Tommy Over a year ago

yes i wanna write it out to the output file but that is the result that i get.

Michel Keijzers Over a year ago

But you write " " instead of "\n"

Tommy Over a year ago

the space is just the space to separate \n:001000 from \n:001000

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