Java split and replace a string with value

Question

I have a following string which I have to split and replace the value on some condition

http://localhost:8080/api/upload/form/{uploadType}/{uploadName}

in which I have to replace the value only for {uploadType}/{uploadName} . I really don't know how to go about to replace them with value.

The strings which are in {uploadType}/{uploadName} can be of any type to replace.

I've tried something like the following :

package com.test.poc;

public class TestString {
public static void main(String[] args) throws ClassNotFoundException {
    String toBeFixed = "http://localhost:8080/api/upload/form/{uploadType}/{uploadName}"; 
    String[] toReplaceWith =toBeFixed.split("{");
for (String string : toReplaceWith) {
    System.out.println("string : "+string);
}   
}

}

but i get the following exception:

Exception in thread "main" java.util.regex.PatternSyntaxException: Illegal repetition
{
    at java.util.regex.Pattern.error(Pattern.java:1713)
    at java.util.regex.Pattern.closure(Pattern.java:2775)
    at java.util.regex.Pattern.sequence(Pattern.java:1889)
    at java.util.regex.Pattern.expr(Pattern.java:1752)
    at java.util.regex.Pattern.compile(Pattern.java:1460)
    at java.util.regex.Pattern.<init>(Pattern.java:1133)
    at java.util.regex.Pattern.compile(Pattern.java:823)
    at java.lang.String.split(String.java:2292)
    at java.lang.String.split(String.java:2334)
    at com.test.poc.TestString.main(TestString.java:9)

EDIT :

this is the method i tried based on Sean Patrick Floyd answer

public String doPOSTPathVariable(String uri,List paramsList) throws IllegalArgumentException, IllegalAccessException, InstantiationException, Exception{
        String uriString="";
        UriComponents uriComponents = UriComponentsBuilder.fromUriString(uri).build();
        for (int j = 0; j<= paramsList.size(); j++) {
            System.out.println("path variable");
            MethodParams methodParams;
            methodParams =(MethodParams) paramsList.get(j);

            if(methodParams.isPrimitive() && methodParams.getDataType()=="boolean"){
                  uriString = uriComponents.expand(true).encode().toUriString();
            }
            if(methodParams.isPrimitive() && methodParams.getDataType()=="java.math.BigDecimal"){
                uriString = uriComponents.expand(123).encode().toUriString();
            }
            if(methodParams.isPrimitive() && methodParams.getDataType()=="java.lang.String"){
                uriString = uriComponents.expand("hexgen").encode().toUriString();
            }
       } 
        return uriString;
    }

but i get following exception :

java.lang.IllegalArgumentException: Not enough variable values available to expand 'uploadName'
    at org.springframework.web.util.UriComponents$VarArgsTemplateVariables.getValue(UriComponents.java:1025)
    at org.springframework.web.util.UriComponents.expandUriComponent(UriComponents.java:443)
    at org.springframework.web.util.UriComponents.access$1(UriComponents.java:431)
    at org.springframework.web.util.UriComponents$FullPathComponent.expand(UriComponents.java:800)
    at org.springframework.web.util.UriComponents.expandInternal(UriComponents.java:413)
    at org.springframework.web.util.UriComponents.expand(UriComponents.java:404)
    at com.hexgen.tools.HexgenClassUtils.doPOSTPathVariable(HexgenClassUtils.java:208)
    at com.hexgen.reflection.HttpClientRequests.handleHTTPRequest(HttpClientRequests.java:77)
    at com.hexgen.reflection.HexgenWebAPITest.main(HexgenWebAPITest.java:115)

Could some one help me on this please?

the no of parameter to be replaced will be deducted at the run time only — Java Questions
– Java Questions, Commented May 2, 2013 at 10:26

Quetzalcoatl · Accepted Answer · 2013-05-02 10:32:32Z

2

Perhaps the UriBuilder?

UriBuilder.fromPath("http://localhost:8080/api/upload/form/{uploadType}/{uploadName}").build("foo", "bar");

(Conveniently happens to use the exact formatting you are using)

edited May 2, 2013 at 10:32

answered May 2, 2013 at 10:20

Quetzalcoatl

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2 Comments

Java Questions Over a year ago

the no of parameter to be replaced will be deducted at the run time only

Quetzalcoatl Over a year ago

With UriBuilder being a builder pattern, you can iteratively add components to it using its convenience methods that return itself. Its exists for your situation exactly like yours, much cleaner than regex.

Sean Patrick Floyd · Accepted Answer · 2013-05-02 10:40:04Z

2

If you use Spring MVC, this functionality is available out of the box with the new URI builder technology.

UriComponents uriComponents =
    UriComponentsBuilder.fromUriString(
        "http://example.com/hotels/{hotel}/bookings/{booking}").build();

URI uri = uriComponents.expand("42", "21").encode().toUri();
// or:
String uriString = uriComponents.expand("42", "21").encode().toUriString();

(In fact you can still use this technology, even if you don't use Spring MVC, but you'll need to have the Spring MVC jar on the Classpath, obviously)

answered May 2, 2013 at 10:40

Sean Patrick Floyd

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2 Comments

Java Questions Over a year ago

I have followed your input but it gives me java.lang.IllegalArgumentException: Not enough variable values available to expand 'uploadName' will update the question now

Sean Patrick Floyd Over a year ago

@Anto this method only works if you know the number of parameters at compile time

Madhusudan Joshi · Accepted Answer · 2013-05-02 10:23:15Z

1

You can try this one :

public class TestString {
public static void main(String[] args) throws ClassNotFoundException {
String toBeFixed = "http://localhost:8080/api/upload/form/{uploadType}/{uploadName}"; 
String[] toReplaceWith =toBeFixed.split("\\{");
for (String string : toReplaceWith) {
System.out.println("string : "+string);
}   
}

}

answered May 2, 2013 at 10:23

Madhusudan Joshi

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Comments

Sumit Bisht · Accepted Answer · 2013-05-02 10:40:56Z

1

UrlBuilder is the solution, but if you are just looking around delimiters, you can also use substrings:

String url = "http://localhost:8080/api/upload/form/{uploadType}/{uploadName}";
int lastSlash = url.lastIndexOf('/');
int secondLastSlash = url.substring(0, lastSlash).lastIndexOf('/');
System.out.println(url.substring(secondLastSlash+1, lastSlash));
System.out.println(url.substring(lastSlash+1));

To remove the curly braces, you can use String.replace('{', '') and String.replace('}', '') on the strings

answered May 2, 2013 at 10:40

Sumit Bisht

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Community · Accepted Answer · 2017-05-23 11:43:19Z

0

A { is a regex meta-character used for range repetitions.

before doing that

toBeFixed = toBeFixed.replaceAll("\\{", "\n");

see docs also :http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html

Similar question :Java String ReplaceAll method giving illegal repetition error?

edited May 23, 2017 at 11:43

CommunityBot

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answered May 2, 2013 at 10:20

Suresh Atta

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1 Comment

Java Questions Over a year ago

http://localhost:8080/api/upload/form/ uploadType}/ uploadName} is the out put if i follow your code, how can i replace those two with value

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