Suppose I have 2D array as follow:
int[][] temp={
{1,2,3,4},
{5,6,7,8},
{9,10,11,12}};
and i want to get sub-array start from X direction 1 to 2 and Y direction 1 to 2 i.e.
{6,7}
{10,11}
can anyone give me solution for above problem.
Here you are
int[][] temp = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 } };
int[][] a = new int[temp.length][];
for (int i = 0; i < temp.length; i++) {
a[i] = Arrays.copyOfRange(temp[i], 1, 3);
}
System.out.println(Arrays.deepToString(a));
output
[[2, 3], [6, 7], [10, 11]]
answering your question in comment if we want to access only [[6, 7], [10, 11]]
int[][] a = new int[2][];
for (int i = 1, j = 0; i < 3; i++, j++) {
a[j] = Arrays.copyOfRange(temp[i], 1, 3);
}
output
[[6, 7], [10, 11]]
As an example without using the Arrays class:
int[][] temp = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 } };
int[][] subArray = new int[temp.length][];
for (int i = 0; i < subArray.length; i++) {
subArray[i] = new int[2];
subArray[i][0] = temp[i][1];
subArray[i][1] = temp[i][2];
}
You can then access any part of subArray that you want. This will access the values [[6, 7], [10, 11]]:
for (int x = 1; x < 3; x++) {
System.out.println(subArray[x][0]);
System.out.println(subArray[x][1]);
}
[Additional] To address the modified question:
If you want to create a smaller array you can play around with the start and end points of the loop, and the indices accessed within the loop, for example this will create the array you ask for:
int[][] subArray = new int[2][];
for (int i = 1; i < temp.length; i++) {
subArray[i-1] = new int[2];
subArray[i-1][0] = temp[i][1];
subArray[i-1][1] = temp[i][2];
}
You could instantiate a new array and loop through the appropriate indices of the original array to initialize the subarray.
