powershell regex remove digit

Question

Using Powershell, I'm trying to remove leading zeros of the numeric part of a string. Here are a couple of examples and expected results:

AB012 needs to become AB12

ABC010 needs to become ABC10

I've tried the following, but it gets rid of all zeros. How can I tell it to only remove the leading zeros? The format of the string will always be letters followed by numbers. However, the length of the letters may vary.

$x = ABC010
$y = $x -replace '[0]'
$y

This will display ABC1, and I wish to display ABC10.

Thanks.

Nate Hekman · Accepted Answer · 2013-05-07 14:32:18Z

2

This regex searches for a letter followed by any number of 0's and keeps the letter in the replacement pattern but strips the zeros:

$x = $x -replace '([a-z])0*', '$1'

answered May 7, 2013 at 14:32

Nate Hekman

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CB. · Accepted Answer · 2013-05-07 14:28:54Z

2

try this regex with look-behind and look-ahead assertions

'(?<=.+)(0)(?=.+)'

the problem is if you have string like "0AB0101" that become"0AB11" in this case use:

'(?<=\D)(0)(?=.+)'

answered May 7, 2013 at 14:28

CB.

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Comments

Shay Levy · Accepted Answer · 2013-05-07 14:39:25Z

0

Here's another option that evaluates the digits as a number:

PS> [regex]::replace('ABC010','(\d+)',{iex $args[0]})
ABC10

Or using the TrimStart method:

PS> [regex]::replace('ABC010','(\d+)',{$args[0].ToString().TrimStart('0')})
ABC10

answered May 7, 2013 at 14:39

Shay Levy

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