dynamic creation of php code from array in php

Question

I have a code to generate php code from an array of words, however the list of words is variable like:

    $list=array(
    "BMW",
    "MUSTANG",
    "DBM",
    "Txt62"
    );

$arrlength=count($list);

for($x=0;$x<$arrlength;$x++)
  {
  echo ' \'' .$list[$x]. '\'' . ' => $this->input->post("'.$list[$x].'") == \'\' ? \'Not defined definido\' : $this->input->post("'.$list[$x].'"),  ';
  echo "<br>";
  }

Is there a better way to do it, like a function that I pass the array of words, and it returns php code?, Is this possible inside php code?

from an array of words, I want to generate php code for each of those words, the problem is, I can not make dynamic php code..} — edgarmtze
– edgarmtze, Commented May 11, 2013 at 20:34
@cMinor ok, you want a new .php file, what does that PHP file do ? — HamZa
– HamZa, Commented May 11, 2013 at 20:35
It catches post values from all fields given a table in MYsql, then generates a code to validate all of the fields — edgarmtze
– edgarmtze, Commented May 11, 2013 at 20:42

adeneo · Accepted Answer · 2013-05-11 20:47:47Z

1

It's not easy to understand what you're trying to do, but if it is to run a function on every item in an array, you can use array_walk for that ?

$list = array(
              "BMW",
              "MUSTANG",
              "DBM",
              "Txt62"
             );

function validate($item, $key) {
    echo ' \'' .$item. '\'' . ' => $this->input->post("'.$item.'") == \'\' ? \'Not defined definido\' : $this->input->post("'.$item.'"),  <br>';
}

array_walk($list, 'validate');

answered May 11, 2013 at 20:47

adeneo

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