Using ternary operator in JavaScript to invoke two functions

Question

Can this be done in JavaScript?

type == 1 ? function1() : function2();

you realize you can type javascript into the address bar of your browser to test it? — Malfist
– Malfist, Commented Oct 31, 2009 at 18:08
Try it yourself. Paste this: javascript:void(true ? alert('t') : alert('f')) — Crescent Fresh
– Crescent Fresh, Commented Oct 31, 2009 at 19:02
I'm just looking back at this question after all these years and it seem's pretty dumb that I didn't test it out on the console before posting it here. I think I was intimidated by the console back then. — Swamy g
– Swamy g, Commented Dec 1, 2015 at 18:59
Question from the title, solution: stackoverflow.com/questions/6678411/… — Miško
– Miško, Commented Feb 2, 2016 at 11:33

Jon Skeet · Accepted Answer · 2009-10-31 17:38:51Z

30

Yes, that's valid code. It will invoke either function1() or function2(), but not both - depending on the value of type.

answered Oct 31, 2009 at 17:38

Jon Skeet

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3 Comments

Andrew Hare Over a year ago

+1 It must be a slow day on SO when Jon Skeet and Ned Batchelder are answering JavaScript questions! :)

Andrew Hare Over a year ago

Got to hit that rep-cap, whatever it takes :D

o01 Over a year ago

It's valid, but JSHint will give a warning when ternary operators are used in this manner. To disable the warning you should set expr: true in your .jshintrc file.

Ned Batchelder · Accepted Answer · 2009-10-31 17:38:54Z

7

It won't invoke two functions. It will invoke one of your two functions.

answered Oct 31, 2009 at 17:38

Ned Batchelder

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