java generic array with iterator

Question

I have a code like the following.

public class DefaultIterator<E> implements Iterator<E> {
private E[] array;
private int i = 0;

public DefaultIterator(E[] array) {
    this.array = array;
}

@Override
public boolean hasNext() {
    return false;
}

@Override
public E next() {
    return array[i++];
}

@Override
public void remove() {

}

}

// here is my execution.
    public Iterator<String> createNewIterator(Iterator<String>... generalIterators)    {
    return new DefaultIterator<Iterator<String>[]>(generalIterators);
}

I am getting the compilation error at the execution code. can somebody explain why it is failing and how to fix it?

Thanks.

What is the compilation error? It will help if you can include it. — Joshua Taylor
– Joshua Taylor, Commented Jun 6, 2013 at 1:35
The constructor DefaultIterator<Iterator<String>[]>(Iterator<String>[]) is undefined — user826323
– user826323, Commented Jun 6, 2013 at 1:39
Mac, I am getting this. cannot convert from DefaultIterator<Iterator<String>> to Iterator<String> — user826323
– user826323, Commented Jun 6, 2013 at 1:40

Tim Bender · Accepted Answer · 2013-06-06 03:11:05Z

3

So the complaint is that none of the generic types match up between the field declaration, the constructor declaration, and the method declaration.

You want:

public Iterator<String> createNewIterator(String... generalIterators)    {
    return new DefaultIterator<String>(generalIterators);
}

edited Jun 6, 2013 at 3:11

answered Jun 6, 2013 at 1:38

Tim Bender

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1 Comment

user826323 Over a year ago

I want 'Iterator<String>' for the return type.

My-Name-Is · Accepted Answer · 2013-06-06 02:00:20Z

0

Your return type is another one than expected! DefaultIterator<Iterator<String>[]> isn't compatible with Iterator<String> Choose DefaultIterator<Iterator<String>[]> as your return type, this should solve it.

answered Jun 6, 2013 at 2:00

My-Name-Is

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