How to pass global variable in javascript function

Question

Let say I have a $_SESSION['password'] and a javascript function.

Here's the javascript function:

<script>  
    function check() {
        var password = '<?php echo $_SESSION; ?>';
        alert(password);
        if (document.FormName.password.value != password)
            alert("password does not match");
    } 
</script>

<html>
//form here
</html>

How come when the alert pop-ups, it will only display nothing? what happened? Is my passing of variable wrong at all?

Check the resultant html in browser. May be password is not set in SESSION. And you did not echo $_SESSION['password'] like you say in question. — Subir Kumar Sao
– Subir Kumar Sao, Commented Jun 11, 2013 at 5:34
This is very wrong. Please don't ever write out the password along with the HTML sent to the client. — techfoobar
– techfoobar, Commented Jun 11, 2013 at 5:37

Code Lღver · Accepted Answer · 2013-06-11 05:35:27Z

1

$_SESSION is an array and this will return blank if you echo it.

You should use the

<?php echo $_SESSION['password']; ?>

It will echo the password that store in Session.

answered Jun 11, 2013 at 5:35

Code Lღver

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1 Comment

Maxim Kumpan Over a year ago

Concise and explains the problem. +1

Bryan · Accepted Answer · 2013-06-11 05:46:35Z

0

<script>
    function check() {    
        var password = "<?=$_SESSION['password']?>";//you forgot ['password'] here       
        alert(password);
        if(document.FormName.password.value != password)
            alert("password does not match");
    } 
</script>

<html>
//form here
</html>

edited Jun 11, 2013 at 5:46

answered Jun 11, 2013 at 5:35

Bryan

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1 Comment

user2429302 Over a year ago

how come I still come up with an error after doing just this var password = '<?php echo $_SESSION['password'] ?>'; alert(password); alerts nothing

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