I have a problem with json. I get this response from server:
{"TESTS":true,"TESTS_VIEW":true,"ORDER":true,"PARAMETERS":true,"VIEW":true}
How can I save this data in array or something else to have schema: key - value?
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you want a class tha holds those values ?Blackbelt– Blackbelt2013-06-17 10:26:36 +00:00Commented Jun 17, 2013 at 10:26
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no, I want array or something else to for example: for key TESTS I want to get value true.edi233– edi2332013-06-17 10:28:05 +00:00Commented Jun 17, 2013 at 10:28
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1but if you have one object why do you need an array?Blackbelt– Blackbelt2013-06-17 10:29:01 +00:00Commented Jun 17, 2013 at 10:29
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4 Answers
Hmm, not sure I understand why you want this. A JSONObject gives you exactly that, have a look at JSONObject.get():
JSONObject json = new JSONObject(yourjsonstringfromserver);
boolean tests = json.getBoolean("TESTS");
Still, if you want to iterate over all values you can do like this:
Map<String, Object> map = new HashMap<String, Object>();
Iterator<String> keys = json.keys();
for(String key : keys) {
try {
Object value = json.get(key);
map.put(key, value);
}
catch (JSONException e) {
// Something went wrong!
}
}
Comments
JSONObject object = YourObjectHere;
Map<String,Boolean> dict = new HashMap<String,Boolean>();
Iterator it = object.keyes();
while( it.hasNext() ){
String key = it.next();
String value = object.get(key);
dict.put( key, value );
}
Solution, more or less. //Written without checking in IDE so may contain bugs/errors
Comments
JSONObject json = new JSONObject(response);
json.getInt(keyA);
json.getString(keyB);
and etc;
Comments
You can using this function with httpResponse is your json string:
public static YourModel parseJson(String httpResponse) {
YourModel objObject = new YourModel();
try {
JSONArray jsonArrayData = new JSONArray(httpResponse);
if (jsonArrayData.length() >= 1) {
for (int i = 0; i < jsonArrayData.length(); i++) {
JSONObject object = new JSONObject(jsonArrayData.get(0));
// Setting value by key json
objObject.setAtrr(object.getString("YourKey"));
}
}
} catch (JSONException e) {
e.printStackTrace();
return null;
}
return objObject;
}
