Javascript replace dynamic text in string

Question

If i have a string as follows:

http:/mydomain.com/index.php/this/is/an/amazing/url/param/560/

and i want to replace the value of 560, what is the way to do this.

Would a regex or string function be best used here and if so what would that be since the value can be different.

i.e.

the value can be anything:

http:/mydomain.com/index.php/this/is/an/amazing/url/param/120/
http:/mydomain.com/index.php/this/is/an/amazing/url/param/200/

also the trailing slash may be missing i.e.

http:/mydomain.com/index.php/this/is/an/amazing/url/param/560

When you say "the value can be anything", do you mean you want to replace any number at the end of the URL, or the value is a dynamic input to the program? — Barmar
– Barmar, Commented Jun 25, 2013 at 20:10
And if the original URL ends with /, does that have to be retained in the result? — Barmar
– Barmar, Commented Jun 25, 2013 at 20:12

deoxxa · Accepted Answer · 2013-06-25 20:38:31Z

3

You could do something like this:

var new_number = 5;

url = url.replace(/\d+(\/)?$/, new_number + "$1");

This looks for numbers, then optionally one slash, then the end of the string. So you won't match things like http://example.com/some/other/1234/numbers.

answered Jun 25, 2013 at 20:38

deoxxa

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2 Comments

maček Over a year ago

Welcome to stackoverflow.com. This is a good answer even though (\/) looks like a vulgar ascii art.

deoxxa Over a year ago

Ha, I suppose it does! I think that just adds to its charm.

Jacob · Accepted Answer · 2013-06-25 20:09:21Z

1

Regex is probably the easiest solution in this case:

url.replace(/\/\d+\/?$/, '/' + newNumber);

This Regex specifically looks for anything ending in a slash, 1 or more digits, then an optional slash.

answered Jun 25, 2013 at 20:09

Jacob

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1 Comment

Mulan Over a year ago

this will result in param123; don't forget to replace the / before the number.

Barmar · Accepted Answer · 2013-06-25 20:09:36Z

0

var regex = new RegExp('\b'+value+'\b');
newurl = url.replace($regExp, newvalue);

answered Jun 25, 2013 at 20:09

Barmar

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