Converting from Python to C List functions

Question

L = [[" " for i in range(10)] for j in range(10)]

for i in range (10):
    L[9][i]="*"
for i in range (10):
        L[8][i]="1"
for i in range (10):
        L[7][i]="*"
for i in range (10):
        L[6][i]="3"
for i in range (10):
        L[5][i]="*"

print(L)
print()

def Check_Lines(l):
    for i in range (10):
        x=l[i].count("*")
        if x == 10:
            print ("LINE IS FULL")
            del l[i]
            l.reverse()
            l.append([" "," "," "," "," "," "," "," "," "," "])
            l.reverse()


Check_Lines(L)
print (L)

I wrote the above function in Python as I am more familiar with the python language. What it does is searches a 10 by 10 list and if a single row is filled with * then it would delete it and put a new empty row at the top.

I know c does not have the list functions I used. Is there any easy way of going about what I am doing?

What have you tried? C language surely doesn't have a native way to manage dynamic lists, what you have are arrays but to use them in a dynamic way you need to work with pointers. — Jack
– Jack, Commented Jun 28, 2013 at 17:58
I didn't know where to begin to rewrite the built in functions with c. I was more of trying to get someone to respond with what you said "Pointers" so I can look it up and understand what I need to do. I don't know the C language at all and I am trying to learn. — user2532857
– user2532857, Commented Jun 28, 2013 at 18:01
Do some research on linked lists. You'll have to implement the list itself, but it'll be an educational experience. :) — Eric Finn
– Eric Finn, Commented Jun 28, 2013 at 19:20

sedavidw · Accepted Answer · 2013-06-28 18:03:23Z

1

In C unfortunately that problem would be pretty difficult. Would require you to allocate a memory block for your matrix. And when you wanted to "remove" a row you'd have to move everything up and free the extra memory at the bottom of the matrix.

If you can use C++ this is much more easily done with STL containers. You could have a vector of vectors. Removing a row would be a call to erase:

l.erase(pos)  // pos is an iterator at the row you'd like to remove

answered Jun 28, 2013 at 18:03

sedavidw

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