I create a dynamic array of pointers like so:
int ** A;
A = new int*[10];
How do I create a dynamic array of const pointers? Where does the const go?
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1You don't do that in C...you might in C++. Which language are you really using? Also, you might want to consider how you'd initialize those constant pointers to something useful. Once they're allocated, you can't change them, so ...?Jonathan Leffler– Jonathan Leffler2013-07-02 03:16:17 +00:00Commented Jul 2, 2013 at 3:16
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C++. Ok, so I want an array of pointers where I can't modify the objects they're pointing to.Frank– Frank2013-07-02 03:22:22 +00:00Commented Jul 2, 2013 at 3:22
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1 Answer
Courtesy of cdecl.org:
A = new int * const bar[10];
That will give you an array 10 long of pointers that can't be set to anything. You should also declare A as:
int * const *A;
Otherwise you'll have const casting problems.
Or perhaps you want an array of 10 pointers to constant int:
a = new const int *a[10];
4 Comments
Jesse Good
The problem is
const objects must be initialized at declaration.
Ted Hopp
@JesseGood - Yep. Don't know what OP is really after.
Frank
Gah my head is about to explode. I'm just after an array of pointers where I can't modify the objects they are pointing to.
Ted Hopp
@Frank - Then it's "array of pointer to const T", not "array of const pointer to T" :) If your head is about to explode, you're in good company. There's a reason a tool like cdecl was invented--everyone needs it!