Using variable in array

Question

Can someone help me how to change value of an array to variable?

I would like to change from this:

class SimpleAuth
{
var $users = array(
    'admin1' => 'password1',  //
    'admin2' => 'password2',  // User 2
    'admin3' => 'password3',  // User 3
    'admin4' => 'password4',  // User 4
);
}

to:

$user = 'admin'; // value from an include file outside the class declaration
$password = 'password'; // value from an include file outside the class declaration

class SimpleAuth
{
var $users = array(
    $user => $password,       // User 1 // here is the error
    'admin2' => 'password2',  // User 2
    'admin3' => 'password3',  // User 3
    'admin4' => 'password4',  // User 4
);
}

I get 500 error. Please help! Thanks

Take a look at your server error log - that should tell you what's gone wrong. — user1864610
– user1864610, Commented Jul 2, 2013 at 15:20
I have updated my question as I didn't know the class declaration makes a difference. — Michael Eugene Yuen
– Michael Eugene Yuen, Commented Jul 2, 2013 at 15:42

user975475 · Accepted Answer · 2013-07-02 15:20:52Z

2

I just checked this code:

$user = 'admin';
$password = 'password';

$users = array(
    $user => $password,       // User 1 // here is the error
    'admin2' => 'password2',  // User 2
    'admin3' => 'password3',  // User 3
    'admin4' => 'password4',  // User 4
);

on this site (http://writecodeonline.com/php/) and it was good, remove the "var" it is not needed.

answered Jul 2, 2013 at 15:20

user975475

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Comments

DevZer0 · Accepted Answer · 2013-07-02 15:30:44Z

1

are you looking for something like this without var. var was used to declare class member variables prior to php 5. it is still supported for backward compatibility but it only has meaning inside a class context.

$users = array(
$user => $password,       // User 1 // here is the error
'admin2' => 'password2',  // User 2
'admin3' => 'password3',  // User 3
'admin4' => 'password4',  // User 4

);

UPDATE, you can't use dynamic values when your defining the class members, as the variables will have no values when the class gets initiated. move your assignment to the __construct. In your case the construct is same as your class name.

function className() {
         $user = 'admin';
$password = 'password';

     $this->users[$user] = $password;
    }

edited Jul 2, 2013 at 15:30

answered Jul 2, 2013 at 15:20

DevZer0

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7 Comments

Michael Eugene Yuen Over a year ago

Yes, it's inside a class declaration

Michael Eugene Yuen Over a year ago

So I just put your code right before the class declaration? Sorry, I am a newbie :p I have just purchased these code from codecanyon for login authentication.

DevZer0 Over a year ago

your class should have the class constructor, which is the initial function that gets called when you initiate the class. Look for a function inside the class which has the same name as the class name, if not look for a function named '__construct' in your class. The code i gave you needs to go inside that function.

Michael Eugene Yuen Over a year ago

Thanks! working on it but doesn't seems easy coz it has lots of functions inside the class. There is no function called '__construct' and neither has function SimpleAuth()

DevZer0 Over a year ago

ok create a function called SimpleAuth and place it in there.

|

Tom G · Accepted Answer · 2013-07-02 15:19:51Z

0

Remove the 'var' in front of your $users variable instantiation

answered Jul 2, 2013 at 15:19

Tom G

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