fopen matlab code in Python

Question

I have the following code written in Matlab:

>>> fid = fopen('filename.bin', 'r', 'b')
>>> %separated r and b
>>> dim = fread(dim, 2, 'uint32');

if I use a "equivalent" code in Python

>>> fid = open('filename.bin', 'rb')  
>>> dim = np.fromfile(fid, dtype=np.uint32)

I got a different value of dim when I use Python.

Someone knows how to open this file with permission like Matlab ('r' and 'b' separated) in Python?

Thanks in advance,

Rhenan

user2304916 · Accepted Answer · 2013-07-03 22:14:44Z

9

From Matlab docs I learn that your third parameter 'b' stands for Big-Endian ordering, is not a permission.

Most probably Numpy uses the little-endian order on your machine. To fix the problem try to specify explicitly the ordering in Numpy (as you do in Matlab):

>>> fid = open('filename.bin', 'rb')
>>> dim = np.fromfile(fid, dtype='>u4')

the dtype string stands for Big-Endian ('>'), unsigned integer ('u'), 4-bytes number.

See also Data type objects (dtype) in Numpy reference.

edited Jul 3, 2013 at 22:14

answered Jul 3, 2013 at 22:09

user2304916

8,1545 gold badges41 silver badges55 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

fopen matlab code in Python

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related