I want to compare 2 NSMutableArray and get different object into third Array. How can i do that ?
Array1 can loop object .
Array1 = "a", "b","c","d","a","b","c";
Array2 = "a", "b", "c";
And then result
Array3 = "d";
Thanks in advance
4 Answers
Use sets for set operations:
NSSet *set1 = [NSSet setWithArray:array1];
NSMutableSet *set2 = [NSMutableSet setWithArray:array2];
[set2 minusSet:set1];
6 Comments
vikingosegundo
@NGOT, are you using really string literals as in the question, or some objects of a custom class?
Martin R
@NGOT: You have to swap
array1 and array2 because in this answer, array2 is the "larger" array.
NGOT
Array1 is array response from server, and array2 is array copy from Array1. I want after server reponse data to array1, I compare array1 and array2, if in Array2 dont have object which from Array1, reloadTable.
Neeku
@H2CO3 This is the best and the most helpful answer I've ever seen! So lovely! Thanks. (:
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You Can try this too.
NSMutableArray *array1 = [[NSMutableArray alloc]initWithObjects:@"1",@"2",@"3",@"1", nil];
NSMutableArray *array2 = [[NSMutableArray alloc]initWithObjects:@"2",@"1", nil];
NSMutableArray *largeArray;
NSMutableArray *shortArray;
if([array1 count] > [array2 count]){
largeArray = array1;
shortArray = array2;
} else {
largeArray = array2;
shortArray = array1;
}
[largeArray removeObjectsInArray:shortArray];
for (NSString *va in largeArray) {
NSLog(@"%@",va);
}
2 Comments
Buntylm
@RanjuPatel like you have array in which you want to check the duplicates (the duplicates are also in the array).
NSMutableArray *gotDiffArry= [[NSMutableArray alloc] init];
for(int i = 0 ; i < FirstArray.count; i++) {
if(i < seconArray.count){
if(![seconArray[i] isEqual:firstArray[i]]){
[gotDiffArry addObject:[NSNumber numberWithInt:i]];
}
} else {
[gotDiffArry addObject:[NSNumber numberWithInt:i]];
}
}
EDITED:
for (int i = 0 ; i < firstArray.count ; i ++)
{
NSString *search = [firstArray objectAtIndex:i];
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY SELF CONTAINS %@", search];
NSMutableArray *temAraay = [secondArray filteredArrayUsingPredicate: predicate];
if(temArray.count >=0 )
{
NSLog("%@", [temArray objectAtIndex:0]);
}
}
I have used the following and got the desired results:
for(int i =0; i<[arraytwo count]; i++)
{
if (![arrayone containsObject:[arraytwo objectAtIndex:i]])
[arraythree addObject: [arraytwo obectAtIndex:i]];
}
NSLog(@"%@",arraythree);
3 Comments
Hot Licks
Probably more efficient than the set approach (for smaller arrays, at least).
Hot Licks
Yeah, it's just that I haven't gone through a "big O" estimation for the various schemes. Probably the set approach is a hair more efficient for large sets, but you likely have to be in the thousands of elements for it to be significant.
[ "d" ], or should it be[ "b", "d" ], your question isn't clear about what 'diff object' means?