Every time I get a variable through $_GET I want to verify that it is indeed an object of the User class.
So:
if (isUser($_GET['valid_user']))
{
...
}
is there a built in function to use instead of this so called "isUser"?
Thanks a lot!
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5 Answers
You can verify any variable for a certain class:
if ($my_var instanceof classname)
however, in your case that will never work, as $_GET["valid_user"] comes from the request and is never going to be an object.
isUser() is probably a custom function from a user management library that authenticates the current session. You need to take a look how that works if you want to replace it.
1 Comment
robsch
For others: note that
classname is not a string - it is the class identifier (that may be imported with the use keyword).There is a function in the PHP language, which might help you:
bool is_a ( object $object , string $class_name )
From the documentation: Checks if the object is of this class or has this class as one of its parents
Comments
you could try this:
if (is_object($_GET['valid_user']))
{
// more code here
}
Comments
is_object to check if it is a object and link below explains how to check which class
Comments
$_GET[] variables are more constants than variables, they are read only .. but happen to be accessed like you would any other $variable.
In your example:
if (isUser($_GET['valid_user']))
{
...
}
I would hope that it would read:
if (isUser($some_sanatized_variable))
.. unless isUser() is what's doing that. 'Variables' that PHP sets don't belong to any class, which illustrates my concern that isUser() may not adequately know what its dealing with.