Syntax error in bash script

Question

On writing few commands at command line, it works, However placing the same in a script file throws error. Here is what I am trying to do:

USER=chandan-jay
REPO=test-1
echo "GitHub UserID: $USER"
echo "Repository Name: $REPO"
str={\"name\":\"$REPO\"}
curl_response=($( curl -u "$USER" -H "Content-Type:application/json" https://api.github.com/user/repos -d $str ))
echo ${curl_response[@]}

when executing above code line after line on shell if works file. When putting them together in a .sh file it throws syntax error (line number 13 is curl_response):

__git_create_repo_CLI.sh: 13: git_create_repo_CLI.sh: Syntax error: "(" unexpected__

Formatting tip: indent each line with four spaces to format a block of code. — icktoofay
– icktoofay, Commented Jul 21, 2013 at 23:26
Are you sure you're running your script using a Bash interpreter? — ruakh
– ruakh, Commented Jul 21, 2013 at 23:26
Do you have #!/bin/bash at the top of your script? If not, it might be defaulting to /bin/sh, which might not support arrays like that. — icktoofay
– icktoofay, Commented Jul 21, 2013 at 23:27
@icktoofay you are right. I tested code with #!/bin/sh and I got error but with #!/bin/bash it works fine. — furas
– furas, Commented Jul 21, 2013 at 23:30

Adil · Accepted Answer · 2013-07-23 05:48:36Z

2

Set your interpreter to bash, like so :

#!/bin/bash

edited Jul 23, 2013 at 5:48

answered Jul 21, 2013 at 23:30

Adil

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Nabarun Chatterjee · Accepted Answer · 2013-07-22 20:10:21Z

1

Try using bash instead of sh while executing the code. Have a look at this for a better explaination http://viewsby.wordpress.com/2011/11/16/shell-script-arrays-syntax-error-unexpected/

answered Jul 22, 2013 at 20:10

Nabarun Chatterjee

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hd1 · Accepted Answer · 2013-07-21 23:36:05Z

1

Does this look like what you want? I just ran the script, unchanged with my username, under bash, which is /bin/sh on Mac OS X and that's what I got.

answered Jul 21, 2013 at 23:36

hd1

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phyrrus9 · Accepted Answer · 2013-07-21 23:33:09Z

-1

Try changing this

curl_response=($( curl -u "$USER" -H "Content-Type:application/json" https://api.github.com/user/repos -d $str ))

to this

curl_response=`curl -u "$USER" -H "Content-Type:application/json" https://api.github.com/user/repos -d $str`

Hope this helps

answered Jul 21, 2013 at 23:33

phyrrus9

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1 Comment

michaelb958--GoFundMonica Over a year ago

-1 No. No no no. No backquotes. Also, this now sets the variable to a scalar rather than an array.

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