How to check if Image exists on server using URL

Question

I am trying to check whether image file is exist on server Or not. I am getting image path with other server.

Please check below code which I've tried,

$urlCheck = getimagesize($resultUF['destination']);

if (!is_array($urlCheck)) {
  $resultUF['destination'] = NULL;
}

But, it shows below warning

Warning: getimagesize(http://www.example.com/example.jpg) [function.getimagesize]: failed to open stream: HTTP request failed! HTTP/1.1 404 Not Found in

Is there any way to do so?

Thanks

@sankalpMishra yes i tried with below answers but due to allow_url_fopen it shows warnings on server SO then i have tried using CURL and it works for me. — Manish Chauhan
– Manish Chauhan, Commented Aug 5, 2013 at 11:15
@PravinS I can not use absolute path coz my image files are on another server and my code is on another server — Manish Chauhan
– Manish Chauhan, Commented Aug 5, 2013 at 11:16
@MakC use get_headers() function, it will return you length, http response and more — PravinS
– PravinS, Commented Aug 5, 2013 at 11:24

William Buttlicker · Accepted Answer · 2013-08-05 07:15:16Z

3

$url = 'http://www.example.com/example.jpg)';
print_r(get_headers($url));

It will give an array. Now you can check the response to see if image exists or not

answered Aug 5, 2013 at 7:15

William Buttlicker

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Comments

Harshal · Accepted Answer · 2013-08-05 07:18:04Z

1

You need to check that the file is exist regularly on server or not.you should used:

is_file .For example

$url="http://www.example.com/example.jpg";

if(is_file($url))
{
echo "file exists on server";
}
else
{
echo "file not exists on server ";
}

answered Aug 5, 2013 at 7:18

Harshal

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Comments

Hassan Saeed · Accepted Answer · 2017-01-23 17:47:50Z

Fastest & efficient Solution for broken or not found images link
i recommend you that don't use getimagesize() because it will 1st download image then it will check images size+if this will not image then it will throw exception so use below code

if(checkRemoteFile($imgurl))
{
//found url, its mean
echo "this is image";
}

function checkRemoteFile($url)
{
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL,$url);
    // don't download content
    curl_setopt($ch, CURLOPT_NOBODY, 1);
    curl_setopt($ch, CURLOPT_FAILONERROR, 1);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    if(curl_exec($ch)!==FALSE)
    {
        return true;
    }
    else
    {
        return false;
    }
}

Note: this current code help you to identify broken or not found url image this will not help you to identify image type or headers

Bora · Accepted Answer · 2013-08-05 07:22:49Z

0

Use fopen function

if (@fopen($resultUF['destination'], "r")) {
    echo "File Exist";
} else {
    echo "File Not exist";
}

answered Aug 5, 2013 at 7:22

Bora

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Comments

Shankar Narayana Damodaran · Accepted Answer · 2013-08-05 07:13:53Z

0

Issue is that the image may not exist or you don't have a direct permission for accessing the image, else you must be pointing an invalid location to the image.

answered Aug 5, 2013 at 7:13

Shankar Narayana Damodaran

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Comments

DevZer0 · Accepted Answer · 2013-08-05 07:17:08Z

0

you can use file_get_contents. This will cause php to issue a warning along side of returning false. You may need to handle such warning display to ensure the user interface doesn't get mixed up with it.

 if (file_get_contents($url) === false) {
       //image not foud
   }

answered Aug 5, 2013 at 7:17

DevZer0

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1 Comment

Eryk Wróbel Over a year ago

It is more recommended to use curl method instead of file_get_contents because the 2nd one is really slow compared to the curl. stackoverflow.com/questions/11064980/…

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