Using regex replace to transform an expression

Question

is it possible to transform an expression like

{op1 == op2, #} && {op3 > op4, 1, 2} && op5 == op6

to

op1 ==_# op2 && op3 >_1_2 op4 && op5 == op6

So, all occurences after the comma should be placed seperated by an underline after the operator (==, >,<,<=, etc...). opX can be any alphanumerical value.

This is not easily done with regex. Not in one pass at least. — Qtax
– Qtax, Commented Aug 6, 2013 at 8:40

KasF · Accepted Answer · 2013-08-06 10:31:34Z

3

After Qtax's comment, I just wrote a solution:

var st = "{op1 == op2, #} && {op3 > op4, 1, 2} && op5 == op6";

var regex = "{.*?}";
for (var match = Regex.Match(st, regex); match.Success; match = Regex.Match(st, regex))
{
    var oldString = match.Value; // {op1 == op2, #} 

    var op = oldString.Split(' ').ToList()[1].Trim(); // == 
    var csv = oldString.Split(',').Select(x => x.Trim()).ToList(); // [0] = "{op1 == op2" [1] = "#}"

    var expression = csv[0].Remove(0,1); // op1 == op2
    csv.RemoveAt(0);

    var extension = "_" + String.Join("_", csv);
    extension = extension.Remove(extension.Length-1); // _#

    var newString = expression.Replace(op, op + extension);

    st = st.Replace(oldString, newString); 
}

edited Aug 6, 2013 at 10:31

answered Aug 6, 2013 at 10:17

KasF

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