Implode variables in PHP

Question

I'm trying to implode variables, but it's not working correctly:

$models = array("$model0, $model1");

$modelfinal = implode("," , $models);

$modelfinal only returns , ,

I'm guessing I'm way off...anybody?

Is $models meant to have only one element, or is that a typo? — user1726343
– user1726343, Commented Aug 7, 2013 at 23:44
I'm not sure I follow, I'm trying to implode $model0 and $model1 — Ken
– Ken, Commented Aug 7, 2013 at 23:45
@Ken: You already have them concatenated: "$model0, $model1" Shouldn’t take anything more. — Ry-
– Ry- ♦, Commented Aug 7, 2013 at 23:46
@Ken what is $model0 and $model1, what does var_dump($model0, $model1) returns? — Prix
– Prix, Commented Aug 7, 2013 at 23:47

score 4 · Accepted Answer · 2013-08-07 23:52:43Z

4

The following statement creates an array with exactly one string in it, which is comprised of the values of two (apparently) undefined variables separated with a comma:

$models = array("$model0, $model1");

The end result is the same as if you had done this:

$models = array(", ");

Now you're imploding it using a comma as the separator, which doesn't do anything since there's only one element in the array (a string with a comma and a space).

Assuming $model0 and $model1 are defined (which is a problem you'll need to look into first), you can get your desired result either by:

directly using $modelfinal = "$model0, $model1",
or by using $models = array($model0, $model1); followed by the implode.

edited Aug 7, 2013 at 23:52

answered Aug 7, 2013 at 23:47

user1726343

Sign up to request clarification or add additional context in comments.

Comments

Ali Akbar Azizi · Accepted Answer · 2013-08-07 23:44:45Z

2

here is your problem "$model0, $model1" change it to this code

$models = array($model0,$model1);

answered Aug 7, 2013 at 23:44

Ali Akbar Azizi

3,5654 gold badges31 silver badges50 bronze badges

5 Comments

Ry- Over a year ago

Why not array($model0, $model1)? Yuck.

Ali Akbar Azizi Over a year ago

I just copy from question, i fix it now

Dave Over a year ago

Not me, but I think it's because this isn't actually his problem (it's a problem, but he's got other problems going on)

Dave Over a year ago

@Prix his output was , ,, which obviously means there's an issue with $model0 and $model1 as well as this

Ali Akbar Azizi Over a year ago

@Dave i think he is using array for two element not one. is is very strange to convert a string to array , then implode that to string again !!

Collectives™ on Stack Overflow

Implode variables in PHP

2 Answers 2

Comments

5 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

5 Comments

Your Answer

Sign up or log in

Post as a guest

Related