I'm not getting the json_encode to work in my php file. Like for instance, I tried this example I got from php.net
<?php
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
echo json_encode($arr);
?>
But nothing works. If i remove the echo statement, then my php works, which means php isn't recognizing the json_encode code.
I'm using PHP 5.4.16. To sum it up, I'm using xampp 1.8.2.
Help please?
It sounds like there could be a fatal error somewhere else in your script. Make sure display_errors is set to On in php.ini.
This question can not be answered without more debug beeing provided.
As in the comments suggested, use these lines before everything to (try to) enable error reporting:
<?php
header('Content-Type: text/plain');
error_reporting(E_ALL);
ini_set('display_errors', true);
ini_set('display_startup_errors', true);
// Json
echo json_last_error();
Use phpinfo(); to obtain information about PHP Version and JSON support.
This snippet will tell you if the json function is available:
<?php
if (!function_exists('json_encode')) {
echo 'PHP not compiled with json support', PHP_EOL;
}
Last but not least, check errors logs
/var/log/httpd*
/var/log/nginx*
/var/log/php-fpm*
/var/log/apache*
.... (linux)
From Where does PHP's error log reside in XAMPP?
\xampp\apache\logs\error.log
or
\xampp\php\logs\php_error_log
json_last_error()to see what error you're getting. php.net/manual/en/function.json-last-error.phpini_set('display_errors', 1); error_reporting(-1);to the top of your file.