Json array in php code

Question

I need to use Json array in the php code. The problem is that I'm in a for loop and need to separate the array in 2 and then want to merge it. but so far it didn't work. I use it to have a graph (jqxChart).

Here is my code

for($i = 0; $i < $nb; $i++){
   if ($i%2 == 1){  
    $time[$i] = (hexdec($hour[$i]));
    $orders1[] = array(
            'OrderDate' => $time[$i],
        );
   }else{ 
    $hour[$i] = $hour[$i] + 1;
    $orders2[] = array(
             'ProductName' => $hour[$i],
    );
  }
}
$orders[] = array_merge_recursive( $orders1[], $orders2[] );

}

echo json_encode($orders);

Thanks

array_merge_recursive( $orders1[], $orders2[] ); is incorrect. The [] operator after a variable is for assignment. You should only be using the brackets if a = is following the expression. By doing $orders[] = array_merge... You are appending the array merge results to $orders, not assigning them. P.S. sorry for the lack of code styling. I'm on my iPad :-( — kuujo
– kuujo, Commented Aug 13, 2013 at 3:21

Janith Chinthana · Accepted Answer · 2013-08-13 04:37:36Z

1

try this code,

$orders1 = array();   
$orders2 = array();  
for($i = 0; $i < $nb; $i++){
  if ($i%2 == 1){  
    ....
    $temp1 = array(
            'OrderDate' => $time[$i],
        );
    array_push($orders1, $temp1);
   }else{ 
    ....
    $temp2 = array(
             'ProductName' => $hour[$i],
    );
     array_push($orders2, $temp2);
   }
  }
}
$orders = array_merge( $orders1, $orders2 );
echo json_encode($orders);

answered Aug 13, 2013 at 4:37

Janith Chinthana

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Comments

Expedito · Accepted Answer · 2013-08-13 04:27:43Z

0

Remove the square brackets. Instead of:

$orders[] = array_merge_recursive($orders1[], $orders2[]);
       ^^                                 ^^          ^^

Just put:

$orders = array_merge($orders1, $orders2);

answered Aug 13, 2013 at 4:27

Expedito

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