Variable and string as array key

Question

I have a problem concerning array keys. I'm trying to result the following array:

$options = array(
    'number 3' => 'number 3',
    'number 6' => 'number 6',
    'number 9' => 'number 9',
    'number 12' => 'number 12'
);

I'm using the following function:

function number_count() {

    $array = array();

    for( $i = 3 ; $i+3 ; $i <= 12 ) {
        $string_i = print_r($i, true);
        $array[$string_i . 'px'] = $string_i . 'px';
    }

    return $array;
}

    $options= number_count();

I know there is some serious error that I can't understand because the page is blocking when I try to execute the code. How I can insert a variable and key, and variable and value in the array?

Marty McVry · Accepted Answer · 2013-08-16 16:39:18Z

2

There's actually an error in your for-loop...

It should be:

for ($i = 3;$i <= 12; $i = $i + 3) {

answered Aug 16, 2013 at 16:39

Marty McVry

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1 Comment

Ziik Over a year ago

Oh, yeah, I didn't saw that. Thanks!

webbiedave · Accepted Answer · 2013-08-16 16:40:42Z

2

Don't use the results of print_r as an associative index. You can just use $i:

for ($i = 3; $i <= 12; $i + 3) {
    $array[$i . 'px'] = $i . 'px';
}

Also, as pointed out by Marty, the increment code should appear as the third expression in your for loop (you have it as the second, so the loop will run infinitely).

edited Aug 16, 2013 at 16:40

answered Aug 16, 2013 at 16:32

webbiedave

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2 Comments

Ziik Over a year ago

Thanks for the tip. +1 I didn't know that there can be a string and integer in the array key.

webbiedave Over a year ago

PHP will automatically cast the integer to a string when using the concatenation operator.

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